1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Otrada [13]
3 years ago
15

Compute the values of the diffusion coefficients for the interdiffusion of carbon in both α-iron (BCC) and γ-iron (FCC) at 900°C

. Which is larger? Explain why this is the case.
Chemistry
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

α-iron (BCC) has faster diffusion rate because of lower values in activation energy and pre-exponential value.

Explanation:

Taking each parameters or data at a time, we can determine the values/a constant for each parameters in the diffusion coefficient equation.

For α-iron (BCC), the diffusion coefficient = pre-exponential value,Ao × e^( -Activation energy,AE)/gas constant,R × Temperature.

Converting the given Temperature, that is 900°C to Kelvin which is equals to 1173.15K.

For α-iron (BCC), the pre-exponential value, Ao = 1.1 × 10^-6, and the activation energy, AE = 87400.

Thus, we have that the diffusion coefficient = 1.1 × 10^-6 × e(-87400)/1173.15 × 8.31.

Diffusion coefficient for α-iron (BCC) = 1.41 × 10^-10 m^2/s.

Also, For the γ-iron (FCC), the pre-exponential value, Ao = 2.3 × 10^-5 and the activation energy, AE = 148,00.

From these values we can see that both the exponential value, Ao and the activation energy for γ-iron (FCC) are higher than that of α-iron (BCC).

Thus, the diffusion coefficient for the γ-iron (FCC) = 2.3 × 10^-5 × e ^-(14800)/8.31 × 1173.15.

Then, the diffusion coefficient for the γ-iron (FCC) = 5.87 × 10^-12 m2/s.

Therefore, there will be faster diffusion in α-iron (BCC) because of lower activation energy and vice versa.

You might be interested in
. The pI is called ________________. The rule of calculating pI of an amino acid is that first, write the dissociation equation
umka21 [38]

Answer:

The isoelectric point is that the <u>pH </u>at which the compound is in an electronically neutral form.

For diss equations<u>, p</u>lease find them in the enclosed file.

The pIs of 2 amino acids:

  • Glutamate: pI = 3,2
  • Histidine: pI = 7,6

Explanation:

Formula for the pI calculation: pI = (pKa1 + pKa2)/2

Given 3 pKa :

  • Acid glutamic with an acid sidechain:

Use the lower 2  pKas (corresponding with 2 -COOH groups)

pKa1 = 2,19; pKa2 = 4,25; so pI = 3,2

  • Histidine with 2 amino groups:

Use the higher 2 pKas ( -COOH group and -NH= group)

pKa1 = 6; pKa2 = 9,17; so pI = 7,6

6 0
4 years ago
The second-order rate constant for the following gas-phase reaction is 0.041 1/MLaTeX: \cdotâs. We start with 0.438 mol C2F4 in
pantera1 [17]

Answer:

134.8 seconds is the half-life (in seconds) of the reaction for the initial C_2F_4 concentration

Explanation:

Half life for second order kinetics is given by:

t_{\frac{1}{2}=\frac{1}{k\times a_0}

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

t_{\frac{1}{2} = half life

k = rate constant

a_0 = initial concentration

a = Final concentration of reactant after time t

We have :

C_2F_4 \longrightarrow \frac{1}{2} C_4F_8

Initial concentration of C_2F_4=[a_o]=\frac{0.438 mol}{2.42 L}=0.1810 mol/L

Rate constant = k = 0.041 M^{-1} s^{-1}

t_{\frac{1}{2}=\frac{1}{k\times a_0}

=\frac{1}{0.041 M^{-1} s^{-1}\times 0.1810 mol/L}

t_{1/2}=134.8 s

134.8 seconds is the half-life (in seconds) of the reaction for the initial C_2F_4 concentration

3 0
3 years ago
What is the half - life formula
VMariaS [17]

well an example, if the half-life of a 50.0 gram sample is 3 years, then in 3 years only 25 grams would remain. During the next 3 years, 12.5 grams would remain and so on.

7 0
3 years ago
5. In the metric system, 1 meter (m) is equivalent to how many centimeters?
adoni [48]

Answer:

C

Explanation:

___________________________

7 0
3 years ago
Why does organic chemistry have a wide variety from compounds primarily based on only two elements? please help
andreev551 [17]

Answer:

Explanation:  Organic chemistry have a wide variety from compounds of the presence of two elements namely

  • Carbon
  • Hydrogen

 Organic molecules comprises of multiple chains of carbon atoms with different  lengths and because of the ability of carbon to bond with many elements, This produces  a variety of compounds which no other atom or element can. The main variety of compounds exists in the combination of carbon and hydrogen forming hydrocarbons which are virtuall everywhere around us

4 0
3 years ago
Other questions:
  • Give two possible reasons why using tap water instead of distilled water could give misleading
    10·1 answer
  • How does pentane and butane differ from each other
    7·1 answer
  • How many electrons are there in second principal energy<br> level(n=2) of a phosphorus atom?
    8·1 answer
  • Q4-P1 is 1.00atm and V1 is 3.00L. We've now changed the volume so V2 is 1.70L. Use Boyle's Law, how much is P2? *Round your answ
    14·1 answer
  • If the solution of HNO3 has a pH of 8 and a pOH of 6 is it an acid, base or neutral
    9·1 answer
  • Read the given equation:
    5·1 answer
  • Josh is washing glasses with soap and water. He is afraid to
    7·2 answers
  • T<br> Question 1<br> What is the chemical formula of cobalt(II) nitrite?
    12·1 answer
  • Why does an object with less mass move faster after a collision with an object with more mass?
    15·2 answers
  • What do nuclear reactions change in the atom? covalent bonds ionic bonds electrons neutrons protons
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!