What do you mean by calcination??

Consider the balanced equation below. 8H2 + S8 Right arrow. 8H2S Based on the mole ratios, what can most likely be predicted? 1

Arte-miy333 [17]

Answer:

8 mol of hydrogen will react with 1 mol of sulfur.

Explanation:

We'll begin by writing the balanced equation for the reaction.

This is given below:

8H2 + S8 —> 8H2S

Now, let us carefully observe the mole ratio of the reactants.

This is illustrated:

The mole ratio of the reactants ( i.e H2 and S8) is 8 : 1

From the balanced equation above,

We can thus, concluded that:

8 moles of H2 will reacted with 1 mole of S8.

7 0

4 years ago

OMG HELP!!!! I SUCK AT SCIENCE

Maksim231197 [3]

Organism are made up of organic molecules consisting of carbon, hydrogen, oxygen, nitrogen, sulfur, and phosphorus.

The answer is B.

6 0

3 years ago

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What is the term for a group of atoms held together by covalent bonds and having an overall positive or negative charge?

madam [21]

Polyatomic ion: a covalently bonded group of atoms that has a positive or negative charge and acts as a unit.

5 0

3 years ago

Read 2 more answers

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0

3 years ago

What is the boiling point of water at an elevation of 1.55×104 ft ?

horsena [70]

The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease
= 308.14 x 0.05 C = 15.407 deg C
deduct this amount to 100
100 – 15.407 = 84.593 C
ANSWER: 85 deg C (rounded to 2 significant figures)

4 0

3 years ago

What do you mean by calcination??​

What do you mean by calcination??