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Gnoma [55]
3 years ago
13

What is the total charge of the nucleus of a carbon atom? (1) –6 (3) +6 (2) 0 (4) +12

Chemistry
1 answer:
NeX [460]3 years ago
3 0
Carbon atomic number ⇒ 6
Carbon mass number ⇒ 12.

Carbon atomic number - Carbon mass number = number of neutrons.
12 - 6 = 6 neutrons.

Proton charge ⇒ +1

The total charge of the nucleus of a carbon atom ⇒⇒⇒ +6.

So the naswer is (3) +6




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sergeinik [125]
<h2>Answer with Explanation</h2>

This hypothesis concludes that the sugar dissolves faster in warm solution has to do with increased molecular motion because the combined power in the warm solution makes molecules in water to travel quicker and sucrose molecules to fluctuate faster which produced a continued evolution favors to make the connections between sucrose molecules easier to succeed. The collisions between the water molecules and the sugar molecules are at a high rate due to increased temperature.

4 0
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Which of the following is an oxidation-reduction reaction? a. HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) b. Pb(C2H3O2)2(aq) + 2 NaCl
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Answer: Option (d) is the correct answer.

Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

(a)    HCl(aq) + LiOH(aq) \rightarrow LiCl(aq) + H_{2}O(l)

Will be written as:

H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b)   Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)

Will be written as:

  Pb^{2+} + 2C_{2}H_{3}OO^{-} + 2Na^{+} + 2Cl^{-} \rightarrow Pb^{2+} + 2Cl^{-} + 2Na^{+} + 2C2H3OO^{-}

Similarly here,  there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(c)   NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)

Will be written as:

Na^{+} + I^{-} + Ag^{2+} + NO^{2-}_{3} \rightarrow AgI(s) + Na^{+} + NO^{2-}_{3}(aq)

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(d)    Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)

So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.

Thus, we can conclude that Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g) is an oxidation-reduction reaction.

7 0
3 years ago
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aleksley [76]

Answer:

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