Answer:
2.3 L
Explanation:
when you have this eqaution you use P1V1T2=P2V2T1.
since you are looking for volume of gas cylinder that means you are looking for V2.
so you have your given P= 1.0 atm, V=2.5L, T=298K.
They ask you to use STP or standard pressure and temperature.
STP P= 1atm, STP T=273 K
so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2
so you now substitue so its now 1*273*2.5/ 1* 298= V
682.5/ 298= V
Lastly V= 2.2902 and you round to tenths so now you have
V= 2.3 L
First, we will get the average pH of the two given values:
average pH = (6.4+8) / (2) = 7.2
At this average pH, the concentration of the acid from the phenol red is equal to the concentration of the base.
pH = 7.2
[H+] = 10^(-7.2) = 6.3 * 10^-8
Phenol red has the general formula HA, this gives us:
HA <.......> H+ + A-
At pH = 7.2, [H+] = [A-]
<span>Ka = [H+][A-]/ [HA]
</span>Ka = [H+] = <span>6.3 x 10^-8</span>
E since its a physical model i.e. you can touch and feel the model :)
Answer:
130.4 grams of sucrose, would be needed to dissolve in 500 g of water.
Explanation:
Colligative property of boiling point elevation:
ΔT = Kb . m . i
In this case, i = 1 (sucrose is non electrolytic)
ΔT = Kb . m
0.39°C = 0.512°C/m . m
0.39°C /0.512 m/°C = m
0.762 m (molality means that this moles, are in 1kg of solvent)
If in 1kg of solvent, we have 0.712 moles of sucrose, in 500 g, which is the half, we should have, the hallf of moles, 0.381 moles
Molar mass sucrose = 342.30 g/m
Molar mass . moles = mass
342.30 g/m . 0.381 m = 130.4 g
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