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Arlecino [84]
3 years ago
9

The diagram and data below represent gas and the conditions of pressure, volume, and temperature of the gas in a rigid cylinder

with a moveable piston. Determine the volume of the gas in the cylinder at STP.

Chemistry
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

2.3 L

Explanation:

when you have this eqaution you use P1V1T2=P2V2T1.

since you are looking for volume of gas cylinder that means you are looking for V2.

so you have your given P= 1.0 atm, V=2.5L, T=298K.

They ask you to use STP or standard pressure and temperature.

STP P= 1atm, STP T=273 K

so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2

so you now substitue so its now 1*273*2.5/ 1* 298= V

682.5/ 298= V

Lastly V= 2.2902 and you round to tenths so now you have

V= 2.3 L

You might be interested in
Can somebody help me with this also plz
just olya [345]

ANSWER:

4 a) Specific elements have more than one oxidation state, demonstrating variable valency.

For example, the following transition metals demonstrate varied valence states: Fe^{2+}, Fe^{3+}, Cr^{2+}, Cr^{3+}, etc.

Normal metals such as Pb^{2+} and Pb^{4+} also show variable valencies. Certain non-metals are also found to show more than one valence state Pb^{3+} and Pb^{5+}.

4 b) Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons.

For example, Carbon-14 is a naturally occurring radioactive isotope of carbon, having six protons and eight neutrons in the nucleus. However, C-14 does not last forever and there will come a time when it loses its extra neutrons and becomes Carbon-12.

5 a) 2Fe + 3Cl_2 → 2FeCl_3    

5 b) 3Pb + 8HNO_3 → 3Pb (NO_3)_2 + 4H_2O + 2NO_2

5 c) Zn + H_2SO_4 → ZnSO_4 + H_2   (already balanced so don't need to change)

5 d) 2H_2 + O_2 → 2H_2O

5 e) 2Mg + 2HCl → 2MgCl + H_2

EXPLANATION (IF NEEDED):

1. Write out how many atoms of each element is on the left (reactant side) and right (product side) of the arrow.

2. Start multiplying each side accordingly to try to get atoms of the elements on both sides equal.

EXAMPLE OF BALANCING:

8 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Yanka [14]

Answer:

Mass of carbon dioxide produced = 52.8 g

Explanation:

Given data:

Mass of carbon react = 14.4 g

Mass of oxygen = 56.5 g

Mass of oxygen left = 18.1 g

Mass of carbon dioxide produced = ?

Solution:

C + O₂     →      CO₂

Number of moles of C:

Number of moles = mass/ molar mass

Number of moles = 14.4 g/ 12 g/mol

Number of moles = 1.2 mol

18.1 g of oxygen left it means carbon is limiting reactant.

Now we will compare the moles of C with CO₂.

                       C             :         CO₂

                        1             :          1

                      1.2           :          1.2

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.2  mol × 44 g/mol

Mass = 52.8 g

8 0
3 years ago
Give the structure of the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane.
Fudgin [204]

the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane is 2-bromo-2,4,4-trimethylpentane.

what is free radical halogenation?

A substitution reaction in which a hydrogen atom is replaced with a halogen atom, via a free radical reaction mechanism. when this reaction is carrid out by bromine radical, it is called free radicle bromination. When bromine (Br{2}) treated with light (hν) it comes to homolytic cleavage of the Br-Br bond and give rise to bromine radicles.

free-radical bromination of 2,2,4−trimethylpentane

Bromination of an alkane includes the substitution of a bromine atom for a hydrogen atom. The following stages will be taken by 2,2,4-trimethylpentane during this reaction:

Initiation reaction:  The production of a bromine free radical requires the initiation of heat or light.

Br - Br ⇒ 2Br·

Propagation: This reaction relies heavily on hydrogen. This reaction is impossible if hydrogen is not present. Because tertiary free radicals are more stable than secondary and primary free radicals, they are favoured in this reaction.

Termination: The remaining free radical of bromide reacts with the tertiary free radical of 2,2,4-trimethylpentane to form 2-bromo-2,4,4-trimethylpentane.

the principal organic product formed by free-radical bromination of 2,2,4−trimethylpentane is 2-bromo-2,4,4-trimethylpentane.

To know more about free radical halogenation, check out:

brainly.com/question/13046867

#SPJ4

7 0
1 year ago
What is the single factor that classifies an element as a transition metal?
klasskru [66]
The answer is b) the highest occupied orbital is a “d”orbital.
Transition metals are metals where the highest energy electrons partially fill the d subshells. There are some elements with complete d subshells but on forming cations they have incomplete d subshells.
These transition metals have some properties that are different from the other metals .
7 0
4 years ago
In a periodic table, dots around an elements symbol indicate the number of valence electrons in an atom ? True Or False
Liono4ka [1.6K]
True,I think.(so don't really count on my answer sorry :D)
6 0
3 years ago
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