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2 years ago

Methyl pentanoate condensed structural formula

Chemistry

1 answer:

Svetlanka [38]2 years ago

6 0

Answer:

C6H12O2 is the formula for Methyl pentanoate

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9. The major human causes of extinction today are

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Answer:

Explanation:

because of over-hunting, poaching, pollution, loss of habitat, the arrival of invasive species, and other human-caused problems

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3 years ago

What type of graph, that isn't a bar graph, would be used to show 3 different classes choices of a favourite program and how eac

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3 years ago

What is the difference between docosahexaenoate (DHA) and 19,20-dihydroxydocosapentaenoate (19,20-DHDP)? Only DHA is a polyunsat

andrew11 [14]

Answer:

Explanation:

The correct answer is 19, 20 DHDP is more polar than DHA. This is as a result of the presence of two hydroxyl groups.

4 0

3 years ago

C=h/[M(T2-T1)] solve for T1

vodka [1.7K]

Explanation:

This is expressing as a subject of a formula of a specie.

This equation is used in solving for specific heat capacity of a material;

equation:

c = $\frac{h}{M(T2 - T1)}$

First cross multiply:

c[M(T2 - T1)] = h

Then multiply both sides by $\frac{1}{c }$ :

$\frac{1}{c }$ x c[M(T2 - T1)] = $\frac{1}{c }$ x h

M(T2 - T1) = $\frac{h}{c}$

Multiply both sides by $\frac{1}{M}$

$\frac{1}{M}$ x M(T2 - T1) = $\frac{1}{M} x \frac{h}{c}$

T2 - T1 = $\frac{h}{Mc}$

Now rearrange to produce;

T1 = T2 + $\frac{h}{Mc}$

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

7 0

3 years ago

Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na

Vedmedyk [2.9K]

Answer:

$pH=13$

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

$HA\rightleftharpoons H^+ + A^-$

Which occurs in aqueous phase, therefore, the law of mass action is written by:

$Ka=\frac{[H^+][A^-]}{[HA]}$

That in terms of the change $x$ due to the reaction's extent we can write:

$1x10^{-20}=\frac{x*x}{0.1M-x}$

But we prefer to compute the Kb due to its exceptional weakness:

$Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}} =1x10^{-6}$

Next, the acid dissociation in the presence of the base we have:

$Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}$

Whose solution is $x=0.0999M$ which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

$pOH=-log([OH^-])=-log(0.0999)=1$

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

$pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13$

Regards.

5 0

3 years ago

Read 2 more answers