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tatyana61 [14]
3 years ago
7

Methyl pentanoate condensed structural formula

Chemistry
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

C6H12O2 is the formula for Methyl pentanoate

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Fructose-2,6-bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys
postnew [5]

Answer:

1. Increased levels of fructose-2,6-bisphosphatase : Activate gluconeogenesis Inhibit glycolysis

2. Activation of fructose-2,6-bisphosphate (FBPase-2) : Activate glycolysis Inhibit gluconeogenesis

3. Increased glucagon levels : Activate gluconeogenesis Inhibit glycolysis

4. Activation of PFK-2 : Activate glycolysis Inhibit gluconeogenesis

5. Increased levels of CAMP : Activate gluconeogenesis Inhibit glycolysis

Explanation:

Glycolysis is the breakdown of glucose molecules in order to release energy in the form of ATP in response to the energy needs of the cells of an organism.

Gluconeogenesis is the process by which cells make glucose from other molecules for other metabolic needs of the cell other than energy production.

Glycolysis and gluconeogenesis are metabolically regulated in the cell by various enzymes and molecules.

The following shows the various regulatory methods and their effects on both processes:

1. The enzyme fructose-2,6-bisphosphatase functions in the regulation of both processes. It catalyzes the breakdown of the molecule fructose-2,6-bisphosphate which is an allosteric effector of two enzymes phosphofructokinasse-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase-1 which fuction in glycolysis and gluconeogenesis respectively.

Increased levels of fructose-2,6-bisphosphatase  activates gluconeogenesis and inhibits glycolysis by its breakdown of fructose-2,6-bisphosphate.

2. Fructose-2,6-bisphosphate increases the activity of PFK-1 and inhibits the the activity of FBPase-1. The effect is that glycolysis is activated while gluconeogenesis is inhibited.

3. Glucagon is a hormone that stimulates the synthesis of cAMP. It fuctions to activate gluconeogenesis and inhibit glycolysis.

4. Phosphosfructikinase-2, PFK-2 is an enzyme that catalyzes the formation of fructose-2,6-bisphosphate. Activation of PFK-2 results the activation of glycolysis and inhibition of gluconeogenesis.

5. Cyclic-AMP (cAMP) synthesis in response to glucagon release serves to activate a cAMP-dependent protein kinase which phosphorylates the bifunctional protein PFK-2/FBPase-2. This phosphorylation enhances the activity of FBPase-2 while inhibiting the activity of PFK-2, resulting in the  activation of gluconeogenesis and inhibition of glycolysis.

7 0
3 years ago
Which of the following materials is most likely to eject an electron when hit by a photon?
Usimov [2.4K]

Answer:sodium

Explanation:

3 0
4 years ago
The distance between a carbon atom and an oxygen atom in the co molecule is how far from the carbon atom is the center of mass o
DENIUS [597]

The distance between a carbon atom and an oxygen atom in the co molecule is 0.63

<h3>What is the distance?</h3>

Distance is the measurement of the farness of two objects from each other.

The distance between the molecules can be calculated by the given formula

xcm = m_1+m_2m_1\times 1+m_2 \times 2

Putting the values in the equation

xcm = 12+1612 \times 0+16 \times 1.1 = 0.63 A^\circ

Thus, the distance between a carbon atom and an oxygen atom in the co molecule is 0.63

Learn more about distance

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5 0
2 years ago
Read 2 more answers
Given the molar absorptivity for a species X of 1600 M-1cm-1 at a wavelength of 270 nm, and 400 M-1cm-1 at a wavelength of 540 n
Andre45 [30]

Answer:

Explanation:

From the given information:

At wavelength = 270 nm

\varepsilon x_1 = 1600 \ m^{-1} \ cm^{-1}  \\ \\  \varepsilon y_1 = 200 \ m^{-1} \ cm^{-1}

At 270 nm

Suppose x is said to be the solution for the concentration of x and y to be the solution for the concentration of y;

Then:

\varepsilon x_1  \ l + \varepsilon y_1  \ l= 0.5 \\ \\ A = A_1 + A_2

1600 xl + 200 yl= 0.5

Divide both sides by 200

8xl + yl = \dfrac{0.5}{200}

8x + y = \dfrac{0.5}{200}l

Use l = 1cm (i.e the standard length)

Then;

8x + y = \dfrac{0.5}{200} ---- (1)

<u>For 540 nm:</u>

\varepsilon x_2 x  \ l + \varepsilon y_2 y  \ l= 0.5  \\ \\ 40 xl + 800 yl = 0.5

x + 20 y = \dfrac{0.5}{400 \ l}

since l = 1

x + 20 y = \dfrac{0.5}{400 \ } --- (2)

Equating both (1) and (2) together, we have:

8x + y - 8x - 160 y = \dfrac{0.5}{200} - \dfrac{0.5 \times 8}{400}  \\ \\  \implies - 159 y = \dfrac{0.5}{200} ( 1 - \dfrac{8}{2}) \\ \\  -159 y = \dfrac{-0.5 \times 3}{200}  \\ \\  159 \ y = 0.0075  \\ \\  y = \dfrac{0.0075}{159} \\ \\  y = 0.00004716 \\ \\ y = 4.7 \times 10^{-5 } \ M

3 0
3 years ago
A 250.0 gram block is placed on a balance. The balance measures the mass of the block as 243.9 grams. What is the percent error
adell [148]
To compute the percent error, you divide the absolute difference between the actual value and the measured value with the actual value. Then, multiply it with 100 to get the percentage. The solution is as follows:

Percent error = (250 - 243.9)/250 * 100
Percent error = 2.44%
7 0
3 years ago
Read 2 more answers
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