Answer:
the electric field strength of this charge is two times the strength of the other charge
Explanation:
Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;
E1/E2 = Q2/Q1
E2 = E1 x Q1/Q2
= E x Q/ (Q/2)
= 2E
Answer:
velocity = 62.89 m/s in 58 degree measured from the x-axis
Explanation:
Relevant information:
Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.
Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.
Before collision Momentum of A = 1000 x 100 =
kg - m/s in the right direction.
Before collision Momentum of B = 2000 x 80 = 1.6 x
kg - m/s in upward direction.
Mass of System of after collision = 1000 + 2000 = 3000 kg
Now applying the Momentum Conservation, we get
Initial momentum in right direction = final momentum in right direction =
And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x
So,
=
m/s
and
m/s
Therefore, velocity is = ![$ \sqrt{V_x^2 + V_y^2} $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7BV_x%5E2%20%2B%20V_y%5E2%7D%20%24)
= ![$ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B%28%5Cfrac%7B100%7D%7B3%7D%29%5E2%20%2B%20%28%5Cfrac%7B160%7D%7B3%7D%29%5E2%7D%20%24)
= 62.89 m/s
And direction is
tan θ =
= 1.6
therefore, ![$ \theta = \tan^{-1}1.6 $](https://tex.z-dn.net/?f=%24%20%5Ctheta%20%3D%20%5Ctan%5E%7B-1%7D1.6%20%24)
=
from x-axis
Answer:
The correct answer is "0.32 mL".
Explanation:
The given values are:
Density of gold bar,
d = 19.3 g/mL
Mass of gold bar,
m = 6.3 grams
Now,
The volume will be:
⇒ ![Density = \frac{Mass}{Volume}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7BMass%7D%7BVolume%7D)
or,
⇒ ![Volume=\frac{Mass}{Density}](https://tex.z-dn.net/?f=Volume%3D%5Cfrac%7BMass%7D%7BDensity%7D)
On substituting the values, we get
⇒ ![=\frac{6.3 \ g}{19.3 \ g/mL}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6.3%20%5C%20g%7D%7B19.3%20%5C%20g%2FmL%7D)
⇒ ![=0.32 \ mL](https://tex.z-dn.net/?f=%3D0.32%20%5C%20mL)
Answer:
88.34 N directed towards the center of the circle
Explanation:
Applying,
F = mv²/r................... Equation 1
F = Force needed to keep the mass in a circle, m = mass of the mass, v = velocity of the mass, r = radius of the circle.
But,
v = 2πr/t................... Equation 2
Where t = time, π = pie
Substitute equation 2 into equation 1
F = m(2πr/t)²/r
F = 4π²r²m/t²r
F = 4π²rm/t²............. Equation 3
From the question,
Given: m = 0.8 kg, r = 0.7 m, t = 0.5 s
Constant: π = 3.14
Substitute these values into equation 3
F = 4(3.14²)(0.7)(0.8)/0.5²
F = 88.34 N directed towards the center of the circle