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soldier1979 [14.2K]
3 years ago
7

An object is swung in a horizontal circle on a length of string

Physics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer: either 3.20s or 1.18s

Explanation:

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What is the motion of the object?
aleksley [76]

Answer:

<em>Thus, the object is accelerating to the left</em>

Explanation:

<u>The Net Force</u>

The net force is the result of adding all the forces as vectors acting on a body.

\vec F=\vec F_1+\vec F_2+...+\vec F_n

Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.

Second Newton's law gives the relation between the net force and the acceleration of the body:

\vec F = m.\vec a

We can see the acceleration is a vector with the same direction as the net force.

The diagram shows two vertical forces and two horizontal forces.

The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.

The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N

Thus, the object is accelerating to the left

4 0
3 years ago
Given this graph plotting velocity versus time, estimate the acceleration of object A at points X and Y respectively.
Nikolay [14]
I think answer should be d. Please give me brainlest let me know if it’s correct
5 0
3 years ago
A car is moving 14.4 m/s. It decelerates at -1.55 m/s^2 for 4.26 s. It then accelerates at 1.83 m/s^2 until it reaches 11.8 m/s.
Aleonysh [2.5K]

The total time is 6.45 s

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use suvat equations.

In the first part,

u_1 = 14.4 m/s (initial velocity)

a_1 = -1.55 m/s^2 (acceleration)

t_1=4.26 s (time of the first part)

So, we can find the velocity of the car after the first part, by using

v_1 = u_1 +a_1 t_1 =14.4+(-1.55)(4.26)=7.8 m/s

This is therefore the initial velocity of the second part:

u_2 = v_1 = 7.8 m/s

a_2 = 1.83 m/s^2 (acceleration in the second part)

v_2 = 11.8 m/s (final velocity)

And therefore,

v_2 = u_2 + a_2 t_2\\t_2=\frac{v_2-u_2}{a_2}=\frac{11.8-7.8}{1.83}=2.19 s

So, the total time is

t=t_1+t_2=4.26+2.19=6.45 s

Learn more about uniformly accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
Identify the reactions of the citric acid cycle that provide reducing power for the electron‑transport chain
svet-max [94.6K]

The reactions of the citric acid cycle that provide reducing power for the electron‑transport chain are as follows:

  • Conversion of isocitrate to α-ketoglutarate
  • Conversion of succinate to fumarate
  • Conversion of α-ketoglutarate to succinyl-coA

<h3>What is citric acid cycle?</h3>

Citric acid cycle also known as kreb cycle is a series of biochemical reactions that involves the synthesis of reduced electron carrier and ATP.

The following steps in the citric acid cycle involves the provision of reducing power for the electron‑transport chain:

  • Conversion of isocitrate to α-ketoglutarate: Isocitrate is converted to α-ketoglutarate as catalyzed by isocitrate dehydrogenase.
  • Conversion of α-ketoglutarate to succinyl-coA: α-ketoglutarate is converted to succinyl-coA as catalyzed by α-ketoglutarate dehydrogenase.

Learn more about citric acid cycle: brainly.com/question/11459709

7 0
2 years ago
Anybody else bored like me
k0ka [10]

Answer: Ye bro kind of

Explanation:

6 0
2 years ago
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