3 years ago

Identify the missing justifications

Mathematics

1 answer:

shepuryov [24]3 years ago

7 0

Answer:

there is nothing there? comment question again and I'll help

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Step-by-step explanation:

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I got the first part but cant figure out the second, help would be appreciated

azamat

Answer:

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Step-by-step explanation:

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Lily wants to make a banquet of 2 dozen flowers. She picked 5 roses, 6 daisies, and 7 tulips. How many more flowers does Lily ne

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Read 2 more answers

Share R86,70 in the ratio 2 : 1

rusak2 [61]

Answer:

2:1

2=5780

1=2890

Step-by-step explanation:

2/2+1=2/3×86,70=5780

1/2+1=1/3×8670=2890

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3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

4 years ago

Identify the missing justifications ​

Identify the missing justifications