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3 years ago

11

I need help on this 6th grader science plants.

1 answer:

krek1111 [17]3 years ago

3 0

Answer:

A - A fruit of vegetable will begin to grow

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What is the role of the greenhouse gases in the atmosphere?

Karolina [17]

Answer:

greenhouse effects are molecules that trap heat on earth atmosphere

7 0

3 years ago

Read 2 more answers

The empirical formula for carbohydrates is CH2O. The molecular weight for a particular carbohydrate is 90.09 grams. What is the

baherus [9]

We find the weight of the empirical formula:
12.0107 + 2 x 1.00794 + 15.9994
= 30.03

Now, we divide the molecular weight by the weight of the empirical formula to find the number of times the empirical formula repeats:
90.09 / 30.03
= 3

The formula is 3(CH₂O)
C₃H₆O₃

6 0

3 years ago

70 points and will give brainliest

ikadub [295]

Answer:

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

Equation of the reaction:

C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
We find the number of moles of the baking powder that went into the reaction using the expression below:

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{15}{84}$ = 0.179mole

From the equation of the reaction, we can find the number of moles of the citric acid:

3 moles of baking powder reacted with 1 mole of citric acid

0.179 moles of baking powder would react with $\frac{0.179}{3}$ :

This yields 0.059mole of citric acid

To find the volume of the citric acid, we use the mole expression below:

Volume of citric acid = $\frac{number of moles}{concentration}$

Volume of citric acid = $\frac{0.059}{0.8}$ = 0.074L

Expressing in mL gives 74mL

4 0

3 years ago

The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera

nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate = $3.45 g\times \frac{32.5}{100}=1.121 mol$

Moles of bicarbonate ion = $\frac{1.121 g/mol}{61 g/mol}=0.01840 mol$

$HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)$

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

$\frac{1}{1}\times 0.01840 mol=0.01840 mol$ of carbon dioxide gas

Moles of carbon dioxide gas n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

$PV=nRT$ (ideal gas equation)

$V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L$

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0

3 years ago

If the half-life of Carbon-14 is 5700 years, how many years would it take a sample to decay from 1 gram to 31.3 mg

andrew-mc [135]

Answer:

28500 years

Explanation:

Applying,

A = A'( $2^{x/y}$ )............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313( $2^{x/5700}$ )

$2^{x/5700}$ = 1/0.0313

$2^{x/5700}$ = 31.95

$2^{x/5700}$ ≈ 32

$2^{x/5700}$ ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

3 0

3 years ago