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Allisa [31]
3 years ago
5

Which of the following accurately describes the behavior of water when subjected to temperature change?

Chemistry
2 answers:
RideAnS [48]3 years ago
7 0

B. The volume of water will increase if cooled from 3°C to 2°C

77julia77 [94]3 years ago
3 0
I believe this is the best one:
B. The volume of water will increase if cooled from 3°C to 2°C.

I don't think D) because water expands from 4°C to 0°C

"When liquid water is cooled, it contracts like one would expect until a temp of approximately 4 degrees Celsius is reached. After that, it expands slightly until it reaches the freezing point."
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Which of the following statements correctly characterizes the subatomic particle
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Its mass is about the same as that of a proton

Explanation:

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What property of water molecules allows water to dissolve many substances
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Its high polarity

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Solvent is the that part of solution which is present in large proportion and have ability to dissolve the solute. In simplest form it is something in which other substance get dissolve. The most widely used solvent is water, other examples are toluene, acetone, ethanol, chloroform etc.

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what is the relationship between electron affinity and atomic radius? why do you think this relationship occurs?
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2 years ago
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Read 2 more answers
Average Molarity for HCl is .391
Ira Lisetskai [31]

Answer:

#1: 0.00144 mmolHCl/mg Sample

#2: 0.00155 mmolHCl/mg Sample

#3: 0.00153 mmolHCl/mg Sample

Explanation:

A antiacid (weak base) will react with the HCl thus:

Antiacid + HCl → Water + Salt.

In the titration of antiacid, the strong acid (HCl)  is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.

Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:

Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl

Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl

Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl

The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.

Thus, mmoles HCl /mg OF SAMPLE<em> </em>for each trial is:

#1: 2.178mmol / 1515mg

#2: 2.253mmol / 1452mg

#3: 2.219mmol / 1443mg

<h3>#1: 0.00144 mmolHCl/mg Sample</h3><h3>#2: 0.00155 mmolHCl/mg Sample</h3><h3>#3: 0.00153 mmolHCl/mg Sample</h3>
8 0
3 years ago
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