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Alenkinab [10]
3 years ago
11

Show a numerical formula for the dilute in the solution

Chemistry
1 answer:
Ksivusya [100]3 years ago
7 0
M1V1=M2V2 M is the molarity and V is the volume.
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5. Students hypothesize that temperature is a limiting factor for the germination of seeds. They carry out an experiment to
Lelechka [254]

Answer:

keep adding to on each term its quit simple

8 0
2 years ago
2. Nitric oxide contains 46.66% nitrogen and 53.34% oxygen. Water contains 11.21% hydrogen and 88.79% oxygen. Ammonia contains 1
Mrrafil [7]

Answer:

The law of reciprocal proportions states that if two elements react individually with a given weight of a third element, the ratio of the masses with which they combine with the third element are either the same or a simple multiple of the ratio of the masses with which they combine with each other

The compounds formed includes;

1) Nitric oxide, NO

Nitrogen = 46.66% × 30.01 = 14

Oxygen = 53.34% × 30.01 = 16

2) Water, H₂O

Hydrogen = 11.21% × 18.01528 = 2

Oxygen = 88.79% × 18.01528 ≈ 16

3) Ammonia, NH₃

Hydrogen = 17.78% × 17.031 ≈ 3

Nitrogen = 82.22% × 17.031 ≈ 14

The ratio of nitrogen to oxygen in nitric oxide = 14:16 = 7:8

The ratio of nitrogen to hydrogen in ammonia = 14:3

The ratio in which hydrogen and oxygen combine with nitrogen = 3/16

The ratio of hydrogen and oxygen combine with each other in water = 2/16

Therefore, the ratio with which hydrogen and oxygen combine with nitrogen, is (2/3) times the ratio with which they combine with each other, which verifies the law of reciprocal proportions

Explanation:

4 0
3 years ago
The goal of bonding is to reach stability by reaching an octet of valence electrons
Artemon [7]
The correct answer is a
8 0
3 years ago
Suppose the formation of nitrosyl chloride proceeds by the following mechanism: step elementary reaction rate constant 1 NO(g) +
adoni [48]

Answer:

Overall reaction equation;

2NO(g) +Cl2(g) -----> 2NOCl (g)

Explanation:

Given

1) NO(g) + Cl2(g) → NOCl2(g)

2) NOCl2(g) + NO(g) → 2NOCl(g)

Overall reaction equation;

2NO(g) +Cl2(g) -----> 2NOCl (g)

k1= [NOCl2]

k-1= [NO] [Cl2]

k2 = [NOCl2] [NO]

Equilibrium for the first equation (reaction 1)

K= k1/k-1 = [NOCl2]/[NO] [Cl2]

Therefore

[NOCl2] = k1/k-1 [NO] [Cl2]

Rate= k2× k1/k-1 [NO]^2 [Cl2]

Rate = Koverall [NO]^2 [Cl2]

Where Koverall= k1k2/k-1

3 0
4 years ago
if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many gram
Romashka-Z-Leto [24]

Answer:

Mass of CO₂ produced  = 5.72 g

Explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles =  2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

                         CH₄             :              CO₂

                           1                 :              1

                        0.146            :           0.146

                         O₂                :               CO₂

                          2                 :                   1

                     0.26                :              1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol ×  44 g/mol

Mass = 5.72 g

4 0
3 years ago
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