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3 years ago

The products

Chemistry

1 answer:

alexandr1967 [171]3 years ago

6 0

Answer:

The products of self-ionization of water are OH⁻ and H⁺.

Explanation:

The water is self ionized according to the equation:

H₂O → OH⁻ + H⁺.

The ionic product for water (Kw) = [OH⁻][H⁺] = 10⁻¹⁴.

Kw is also called "self-ionization constant" or "auto-ionization constant".

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You must make an aqueous solution that will be a good conductor of electricity. You can pick two substances to add to the water.

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The acid and the salt are the answers

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3 years ago

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This gas can be formed if a hydrogen bomb is detonated.

Levart [38]

Answer:

Helium.

Explanation:

Hydrogen in the bomb is used in the process of detonation. A stream of tritium, an isotope of hydrogen is released and this fissionable material is very unstable thus it turns during the detonation to helium 3. This triggers a series of reactions that produce large amounts of heat to the surrounding environment causing destruction.

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3 years ago

Given a solution with a hydroxide ion concentration, oh=3.73×10^-5,what is the ph

Stells [14]

Answer:

pH = 9.73

Explanation:

pOH is the negative logarithm of the molar concentration of hydroxide ions and pH is the negative logarithm of the concentration of hydronium ions.

The mathematical expression to determine pOH is:

$pOH=-\log [OH^-]$

Where [OH⁻] means the molar concentration of hydroxide ions.

Substituting:

$pOH=-\log {(3.73\times 10^{-5})$

$pOH=4.43$

pH and pOH are related by the equation:

$pH+pOH=14$

From which:

$pH=14-pOH\\\\pH=14 - 4.43\\\\pH=9.57\leftarrow answer$

8 0

3 years ago

Consider the following reaction: CHCl3(g) + Cl2(g) → CCl4(g) + HCl(g) The initial rate of the reaction is measured at several di

Ira Lisetskai [31]

Answer : The correct rate law for the reaction is,

$\text{Rate}=k[CHCl_3][Cl_2]^{1/2}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$CHCl_3(g)+Cl_2(g)\rightarrow CCl_2(g)+HCl(g)$

Rate law expression for the reaction:

$\text{Rate}=k[CHCl_3]^a[Cl_2]^b$

where,

a = order with respect to $CHCl_3$

b = order with respect to $Cl_2$

Expression for rate law for first observation:

$0.0035=k(0.010)^a(0.010)^b$ ....(1)

Expression for rate law for second observation:

$0.0069=k(0.020)^a(0.010)^b$ ....(2)

Expression for rate law for third observation:

$0.0098=k(0.020)^a(0.020)^b$ ....(3)

Expression for rate law for fourth observation:

$0.027=k(0.040)^a(0.040)^b$ ....(4)

Dividing 1 from 2, we get:

$\frac{0.0069}{0.0035}=\frac{k(0.020)^a(0.010)^b}{k(0.010)^a(0.010)^b}\\\\2=2^a\\a=1$

Dividing 2 from 3, we get:

$\frac{0.0098}{0.0069}=\frac{k(0.020)^a(0.020)^b}{k(0.020)^a(0.010)^b}\\\\1.42=2^b\\b=\frac{1}{2}$

Calculation used :

$1.42=2^b\\\log (1.42)=b\log 2\\\log (\frac{1.42}{2})=b\\b=0.5=\frac{1}{2}$

Thus, the rate law becomes:

$\text{Rate}=k[CHCl_3]^1[Cl_2]^{1/2}$

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3 years ago

given a mixture of lead to oxide ammonium chloride and sodium chloride describe how a mixture can be separated to obtain a sampl

wariber [46]

Answer:

There are way in separating mixtures of chloride salts such as that of sodium chloride and ammonium chloride. It can be done by crystallization, filtration, and sublimation. The easiest method among the three is separation by sublimation.

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3 years ago