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3 years ago

If you can walk 2.1 miles in 35 minutes, how many days will take you to con

Chemistry

1 answer:

mel-nik [20]3 years ago

8 0

Answer:

HINT: calculate how much distance you walk in one minute(35 divided by 2.1), then multiply that by 60 to find how far you'll walk in an hour.

You might be interested in

What property is used to calculate the ph of a solution

icang [17]

A. The concentration is in mol/L

7 0

4 years ago

What is the molarity of a 5.0 L solution that contains 0.5 moles of KNO3

pashok25 [27]

Answer:

Molarity of a 5.0 L solution that contains 0.5 moles of KNO3 is 0.1 M

Explanation:

Molarity : It is used to express the concentration of the solution and defined as total moles of solute present in one liter of solution .

$Molarity =\frac{moles\ of\ solute}{volume\ of\ solution(L)}$

Moles of KNO3 = 0.5 (given)

Volume of solution = 5.0 L

Substitute the value in given formula ,

$Molarity =\frac{0.5\ moles }{5.0\ L}$

on calculation,

Molarity = 0.1 mol/L

Molarity = 0.1 M

(M = mol/L)

8 0

4 years ago

What is the mass in grams of 7.23 miles of dinitrogen trioxide?

nevsk [136]

Answer:

549.563868

Explanation:

1 mole is equal to 1 moles N2O3, or 76.0116 grams. so 76.0116 x 7.23 = 549.563868

3 0

3 years ago

a 1.642 g sample of calcium bromide is dissolved in enough water to give 469.1 mL of solution what is the bromide ion concentrat

aleksklad [387]

The bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.

No of moles of calcium bromide is calculated as follows:

moles = 1.642 ÷ 199.89 = 8.215 × 10-³moles

Molarity = 8.215 × 10-³moles ÷ 469.1mL = 1.75 × 10-⁵M

Therefore, the bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.

Learn more about concentration at: brainly.com/question/10725862

#SPJ1

4 0

2 years ago

A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution

madam [21]

<u>Answer:</u> The initial pH of the HCl solution is 3

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL$

Putting values in above equation, we get:

$1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M$

1 mole of HCl produces 1 mole of $H^+$ ions and 1 mole of $Cl^-$ ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.001M$

Putting values in above equation, we get:

$pH=-\log (0.001)\\\\pH=3$

Hence, the initial pH of the HCl solution is 3

6 0

3 years ago