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Aleks04 [339]
3 years ago
8

An equilibrium mixture of N2, O2and NO gases at 1500K is determined to consist of 6.4 x 10-3Mof N2, 1.7 x 10-3M O2, and 1.1 x 10

-5M NO. Write the equilibrium expression and solve for the equilibrium constant (Keq) for the systemat this temperature?
Chemistry
1 answer:
sp2606 [1]3 years ago
4 0

Answer

                    Explanation:O2 = 1.7×10-3M;

N2 = 6.4×10-3M;

NO = 1.1 10-5M.

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A negatron emission

Explanation:

We know that radioactivity orginates from instability of the nucleus. When the nucleus is unstable, radioactive emissions are produced in the form of any of these rays:

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In balancing nuclear reactions we make sure that the charges on both sides must be conserved and that the mass number and atomic numbers conserved too. This means that the sum of mass number and atomic numbers on both side of the reaction must be equal.

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For the given radioactive reaction:

²³¹₉₀Th → ²³¹₉₁Pa + ?

From this equation, we see that the mass number is conserved but the atomic number is not.

The mass number is the superscript whereas the atomic number is the subscript.

Let's say the decay produces an emission of a particle denoted by X

²³¹₉₀Th → ²³¹₉₁Pa + ᵃₙX

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For the charges and masses to be conserved, X must have mass number of 0 and an atomic number of -1.

Checking:

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a = 231 - 231 = 0

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With X having a mass number of 0 and an atomic number of -1, we have a beta particle emission. Specifically, a negatron has been emitted.

A negatron is denoted as ⁰₋₁β which perfectly makes the equation conserved and suits the description of X.

The complete equation is thus written as:

²³¹₉₀Th → ²³¹₉₁Pa + ⁰₋₁β + energy

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