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omeli [17]
3 years ago
12

I need help!!! I have until 9pm but extra credit if we turn it in before that

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer: H... I think

Step-by-step explanation:

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How much money should a student place in a time deposit in a bank that pays 1.1% compounded annually so that he will have Php 20
STatiana [176]

Let us say that:<span>
   P = present value
   F = future value
    i = interest rate
   n = period

P = F / [ (1 + i ) ^n ]
P = 200000 / [ (1 + 0.011) ^6 ]
P = 187293.65

<span>Therefore the student must put up Php 187,293.65</span></span>

5 0
3 years ago
 A tree casts a shadow that is about 10 ft long. Javier, who is about 5 ft tall, is standing near the tree. Javier’s shadow is a
spin [16.1K]
The tree is 11ft  
explanation: javier is 5ft 5-1 =4
11-1=10 <span />
4 0
4 years ago
Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is
igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

x=0(mod5)

x=8(mod11)

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

x=5m

x=11n+8

5m\cong 11n+8

Now, we can say that m>n because m and n are positive integers.

For n=1,

5m=11(1)+8=19

5m=19

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

5m=11(2)+8

5m=30

m=6

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

x=5(6)=30

Therefore the smallest positive integer solution to the given system of congruences is 30.

8 0
3 years ago
10+x/2
Pavlova-9 [17]

Answer:

The answer will be 12 please mark me as brainliest

6 0
3 years ago
Which functions domain consists of all real numbers except -2?
Eddi Din [679]

Answer:

option (a) f(x)= 1/x+2

Step-by-step explanation:

(a) f(x) = 1/ x+2

To find the restriction for domain , we set the denominator =0  and solve for x

x+2 =0, so x=-2

When x=-2  then denominator becomes 0 that is undefined.

So, domain is all real numbers except -2

(b) f(x)= 2x

In this function, there is no denominator or square root or log function

so there is no restriction for x, hence domain is all real numbers

(c) f(x) = 2x-2

In this function, there is no denominator or square root or log function

so there is no restriction for x, hence domain is all real numbers

f(x) = 1/ sqrt(x+2)

if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined

x+2>0, x>-2

Hence domain is all real numbers that are greater than -2

8 0
4 years ago
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