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Gre4nikov [31]
3 years ago
5

Go to the To Scale tab at the bottom of the simulation, and select Path from the central menu on the right. Set up a Planet-Moon

simulation. Use the sliders to make both the planet and the moon as massive as possible, and then begin the simulation. What do you notice about the moon’s motion when it is closest to the planet? What about when it is farthest away?
Chemistry
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

Go to the To Scale tab at the bottom of the simulation, and select Path from the central menu on the right. Set up a Planet-Moon simulation. Use the sliders to make both the planet and the moon as massive as possible, and then ... What do you notice about the moon's motion when it is closest to the planet?

Explanation:

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How many grams of C3H8 would be needed to produce 6.39 grams of CO2?
just olya [345]

Answer:

2.13g

Explanation:

Atomic mass of CO2 =  12 + 32 = 44g/Mol

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Reaction

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3 years ago
A chemist needs 500.0 mL of a 1.500 M perchloric acid solution. The stockroom provides the chemist with
Lynna [10]

Answer:-  47.62 mL

Solution:- It is a dilution problem where we are asked to calculate the volume of 15.75 M perchloric acid solution required to make 500.0 mL of 1.500 M solution.

For solving this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 is the concentration of the concentrated solution and V_1 is it's volume.

M_2 is the concentration of the diluted solution and V_2 is it's volume.  Let's plug in the values in the equation and solve it for V_1 .

15.75M(V_1)=1.500M(500.0mL)

On rearranging this for V_1 :

V_1=\frac{1.500M(500.0mL)}{15.75M}

V_1=47.60mL

So, 47.62 mL of 15.75 M perchloric acid are required to make 500.0mL of 1.500 M solution.

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4 years ago
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Answer:

Answer

Explanation:

7 0
4 years ago
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