Answer:
All of alpha-ketoglutarate formed in the citric acid cycle would contain the radioactive 
while none of succinate would contain , and all of carbon dioxide released would contain .
Explanation:
When oxaloacetate in the citric acid cycle is labeled with in carboxyl carbon atom which is farthest from keto group, alpha ketoglutarate formed from this oxaloactetate has the full radioactive label. In the next step, the carboxylic group (that contains the ) is eliminated in the form of the release of the carbon dioxide and succinate is formed. Succinate thus will not have radioactivity. 
released had all the radioactivity.
Answer:
4.74 × 10³ mg
Explanation:
Given data
- Health risk limit for chloroform in groundwater: 60.0 g/L
- Volume of the sample of groundwater: 79.0 mL = 79.0 × 10⁻³ L
The maximum mass of chloroform that there could be in the sample of groundwater to meet the standards are:
79.0 × 10⁻³ L × 60.0 g/L = 4.74 g
1 gram is equal to 10³ milligrams. Then,
4.74 g × (10³ mg/1 g) = 4.74 × 10³ mg
Note: We must keep the units we use consistent. The Cp is given in cal/gC so we will use cal for energy, grams for mass and C for temperature.
1)
Heat supplied can be calculated using:
Q = mCpΔT; where m is the mass, Cp is the specific heat capacity and ΔT is the temperature change.
Q = 367 x 0.092 x (60 - 23)
Q = 125 Cal
2)
Using the same equation:
125 = 60 x 0.092 x (T - 23)
T = 45.6 C
