How many electrons can the n=4 shell hold? a. 8b.16c.32d.64?

Chemistry

2 answers:

ra1l [238]3 years ago

6 0

The maximum the fourth shell can have is 32.

belka [17]3 years ago

3 0

Answer:

c.32

Explanation:

Hello,

In this case, it is possible to determine it by building the subshells organization for the first four shells as shown below:

$1s^2\\2s^2\ 2p^6\\3s^2\ 3p^6\ 3d^{10}\\4s^2\ 4p^6\ 4d^{10}\ 4f^{14}$

In such a way, counting the electrons at the n=4 shell, the result is 32 (2+6+10+14), so the answer is c.

Best regards.

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$\boxed {\boxed {\sf Approximately \ 147 \ g\ Ag}}$

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Convert Atoms to Moles

The first step is to convert atoms to moles. 1 mole of every substance has the same number of particles: 6.022 ×10²³ or Avogadro's Number. The type of particle can be different, in this case it is atoms of silver. Let's create a ratio using this information.

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We are trying to find the mass of 8.23 ×10²³ silver atoms, so we multiply by that number.

$8.23 *10^{23} \ atoms \ Ag *\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}$

Flip the ratio so the atoms of silver cancel. The ratio is equivalent, but places the other value with units "atoms Ag" in the denominator.

$8.23 *10^{23} \ atoms \ Ag *\frac{1 \ mol \ Ag}{6.022*10^{23} \ atoms \ Ag}$

$8.23 *10^{23} *\frac{1 \ mol \ Ag}{6.022*10^{23} }$

Condense into one fraction.

$\frac{8.23 *10^{23} }{6.022*10^{23} } \ mol \ Ag$

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Convert Moles to Grams

The next step is to convert the moles to grams. This uses the molar mass, which is equivalent to the atomic mass on the Periodic Table, but the units are grams per mole.