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2 years ago

13

Which describes a substance with a high index of refraction?

2 answers:

icang [17]2 years ago

8 0

Which describes a substance with a high index of refraction?

*It causes light to slow down significantly. *

Mazyrski [523]2 years ago

5 0

Answer:

It causes light to slow down significantly

Explanation:

The index of refraction of a substance describes the speed of light in that substance, as a ratio of the speed of light in vacuum to its speed in that substance.

just search it up and there is your answer

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Which of the following is a change of state?

Step2247 [10]

Answer:

I think C. Hope this Helps!

Explanation:

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2 years ago

Which represents the correct equilibrium constant expression for the reaction below? Cu(s)+2Ag+(aq)<->Cu2+(aq)+2Ag(s)

balu736 [363]

K(eq) = concentration of products/concentration of reactant = [Cu+2] / [Ag+]^2
Activity of pure solid and liquid is taken as 1.
Hence last option is correct.
Hope this helps, have a great day ahead!
I hope this helps you alot
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2 years ago

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Gnoma [55]

What volume of 2.50 m lead ll nitrato

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2 years ago

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A system of ideas that explains many related observations and is supported by a large body of evidence collected through scienti

wlad13 [49]

B. Theory
The hypothesis that stand the test of time (often tested and never rejected) is called theory. A theory is supported by a great dealcof evidence.

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2 years ago

4.60 mL of 0.1852 M HNO3 is titrated to the phenolphthalein indicator endpoint with 27.35 mL of a KOH solution. What is the mola

Kamila [148]

Answer:

$M_{base}=0.0311M$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

$n_{acid}=n_{base}$

Which in terms of molarities and volumes is:

$M_{acid}V_{acid}=M_{base}V_{base}$

Thus, we solve for the molarity of the base (KOH) to obtain:

$M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M$

Regards!

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2 years ago