Shape of PCl₆⁻¹, is octahedral.
Hybrdisation of PCl₆⁻¹ is sp³d².
This can be seen the image attached.
The angle between phosphorous and chlorine is 90⁰C. As it has octahedral geometry.
So the answer is as follows:
Shape of PCl₆⁻¹, is octahedral.
Hybrdisation of PCl₆⁻¹ is sp³d².
The angle between phosphorous and chlorine is 90⁰C.
Answer:
Shape- square planar , hybridisation-sp3
Explanation:
Shape:
- VSPER theorey is used to determine both electron geometry and molecular geometry of a molecule.(PtCl4)2 molecular geometry is square planar
- Hybridisation:It undergoes sp3 hybridisation.since there are 2 unpaired electrons in this case, it is paramagnetic in nature
-
<u>Given:</u>
Initial amount of carbon, A₀ = 16 g
Decay model = 16exp(-0.000121t)
t = 90769076 years
<u>To determine:</u>
the amount of C-14 after 90769076 years
<u>Explanation:</u>
The radioactive decay model can be expressed as:
A = A₀exp(-kt)
where A = concentration of the radioactive species after time t
A₀ = initial concentration
k = decay constant
Based on the given data :
A = 16 * exp(-0.000121*90769076) = 16(0) = 0
Ans: Based on the decay model there will be no C-14 left after 90769076 years
Answer:
Activation energy is needed so reactants can move together, overcome forces of repulsion, and to begin breaking bonds.
Explanation:
Answer
:
2. Hydrogen forms bonds through the overlap of 1s atomic orbitals and the sharing of electrons between atoms. Carbon forms bonds through the overlapping of sp hybrid atomic orbitals and the sharing of electrons between carbon atoms.
Explanation:
The H-H bond is formed by the overlap of two 1s orbitals and the sharing of electrons between the two atoms.
A carbon atom must use the overlap of hybridized atomic orbitals and the sharing of electrons to bond with another carbon atoms.
1. is <em>wrong</em> because H can use only its <em>1s orbital</em> for bonding.
3. is <em>wrong</em> because C must <em>share electrons</em> to form a carbon-carbon bond.
4. is <em>wrong</em> because <em>C does NOT use overlapping of 2s orbitals</em> for bonding. It uses the overlap of hybridized orbitals.
5. is <em>wrong</em> because H must <em>share electrons</em> to form an H-H bond.
