Answer:
Dendrochronology is the study of data from tree ring growth. Due to the sweeping and diverse applications of this data, specialists can come from many academic disciplines. There are no degrees in dendrochronology because though it is useful across the board, the method itself is fairly limited. Most people who enter into studying tree rings typically come from one of several disciplines: 1.
Explanation:
Along with the advantages of dendroclimatology are some limitations: confounding factors, geographic coverage, annular resolution, and collection difficulties. The field has developed various methods to partially adjust for these challenges.
There are multiple climate and non-climate factors as well as nonlineareffects that impact tree ring width. Methods to isolate single factors (of interest)
Answer: 30.27 g
Explanation:
Since the silver is in units of atoms, we have to use Avogadro's number and molar mass.
Avogadro's number: 6.022×10²³ atoms/mol
Molar Mass: 107.87 g/mol
Now that we have everything we need, we can convert atoms to grams.
Answer:
Molar mass of CH18 =30
Explanation:
CH18
Molar mass of carbon = 12
Molar mass of hydrogen (H) = 1
CH18 = 12 + 1 (18) = 12 +18 = 30
Answer:
There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst. 4. Reduce pressure way below the limit 269 kPa.
Explanation:
Answer:
24.47 L
Explanation:
Using the general gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = 0.0821 Latm/molK
T = temperature (K)
According to the provided information in this question,
P = 1.0 atm
V = ?
n = 1 mol
T = 25°C = 25 + 273 = 298K
Using PV = nRT
V = nRT ÷ P
V = 1 × 0.0821 × 298 ÷ 1
V = 24.465 ÷ 1
V = 24.465
V = 24.47 L
