HEY DEAR..
<u>PHYSICAL</u><u> </u><u>CHANGE</u>
<em>Those</em><em> </em><em>Changes</em><em> </em><em>in</em><em> </em><em>which</em><em> </em><em>no</em><em> </em><em>new</em><em> </em><em>substances</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>are</em><em> </em><em>called</em><em> </em><em>physical</em><em> </em><em>changes</em><em>.</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>temporary</em><em> </em><em>changes</em><em> </em><em>which</em><em> </em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>reversed</em><em> </em><em>easily</em><em> </em><em>to</em><em> </em><em>form</em><em> </em><em>the</em><em> </em><em>original</em><em> </em><em>substance</em><em>.</em>
<u>Example</u><u>:</u><u>-</u> <em>Melting</em><em> </em><em>of</em><em> </em><em>ice</em><em> </em><em>,</em><em> </em><em>Making</em><em> </em><em>a</em><em> </em><em>solution</em><em>, </em><em> </em><em>Glowing</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>electric</em><em> </em><em>bulb</em><em> </em><em>,</em><em> </em><em>freezing</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>etc</em><em>.</em>
<u>CHEMICAL</u><u> </u><u>CHANGE</u>
<em>Those</em><em> </em><em>changes</em><em> </em><em>in</em><em> </em><em>which</em><em> </em><em>new</em><em> </em><em>substances</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>are</em><em> </em><em>called</em><em> </em><em>chemical</em><em> </em><em>changes</em><em>. </em><em>it</em><em> </em><em>means</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>permanent</em><em> </em><em>changes</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>usually</em><em> </em><em>irreversible</em><em>. </em>
Example:- <em>Burning</em><em> </em><em>of</em><em> </em><em>charcoal</em><em>,</em><em> </em><em>fuels</em><em> </em><em>and</em><em> </em><em>cutting</em><em> </em><em>of</em><em> </em><em>trees</em><em>, </em><em> </em><em>even</em><em> </em><em>digestion</em><em> </em><em>of</em><em> </em><em>food</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>chemical</em><em> </em><em>change</em><em>. </em>
HOPE ITS HELPFULLL
BE BRAINLY.
Answer:
Supersaturated.
Explanation:
Hello there!
In this case, according to this solubility chart, we infer that for NH3, the solubility starts at 90 grams of NH3 that are soluble in 100 g of water at 0 °C and ends in about 8 g in 100 g of water at 100 °C for a saturated solution.
However, since we are asked for the solubility of NH3 at 20 °C, we can see that, according to the table and the curve for NH3, about 52 g of NH3 are soluble in 100 g of water; thus, for the given 60 g of NH3, we will say that 8 grams will remain undissolved, and therefore, this solution will be supersaturated.
Regards!
It looks like we are solving for a pressure. All that is required is some algebraic manipulation to find our pressure in mmHg.
Given:
(5.0 m³)(7.5 mmHg) = (P)(4.0m³)
Multiply:
37.5 = 4.0P
Divide:
9.375 = P
P = 9.4 mmHg (remember sig figs)
<h3>
Answer:</h3>
9.4 mmHg
Answer:
2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.
12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution
Explanation:
First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:
- Ca: 40 g/mole
- F: 19 g/mole
So the molar mass of CaF₂ is:
CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole
Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=2.05*10⁻⁵
<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>
Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF₂= 1000 g
Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=12.82
<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>
Answer:
yuh
Explanation:
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