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Volgvan
3 years ago
11

Two objects, A and B, have the same volume and are completely submerged in a liquid, although A is deeper than B. Which object,

if either, experiences the greater buoyant force?
a. Object B, because the closer an object is to the surface, the greater is the buoyant force.
b. Both objects experience the same buoyant force.
c. Object A, because, being at a greater depth, it experiences a greater pressure.
Physics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:it would probably be C

Explanation:

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the first s-wave reaches a seismic station 22 minutes after an earthquake occurred. how long did it take the first p-wave to rea
Naddik [55]

The time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.

<h3>Time of travel of the P-wave</h3>

In rock, S waves generally travel about 60% the speed of P waves, and the S wave always arrives after the P wave.

<h3>Relationship between speed and time</h3>

v ∝ 1/t

v₁t₁ = v₂t₂

t₁/t₂ = v₂/v₁

t₁/t₂ = 0.6v₁/v₁

t₁/t₂ =  0.6

t₁ = 0.6t₂

t₁ = 0.6 x 22 mins

t₁ = 13.2 mins

Thus, the time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.

Learn more about P-waves here: brainly.com/question/2552909

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7 0
2 years ago
use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help ​
kati45 [8]

Answer:

L = 3.51

Explanation:

Pendulum equation is T = 2pi\sqrt{L/9.81}

T = 1.5 and we are solving for L

1.5=2\pi \sqrt{L/9.81}

square both sides to get 2.25 = 2\pi ( L/9.81)

multiply both sides by 9.81 then divide by 2 and 3.14 as a substitue for pi. The answer should be about 3.51 in length

L = 3.51

If this helps, mark me brainliest pls

3 0
3 years ago
The force of friction between an object and the surface upon which it is sliding is 14N and the coefficient of friction between
Nat2105 [25]

Answer:

14 x 0.27 = 3.78 is your answer

Explanation:

the question is asking for the weight of the object so you multiply and get 3.79

5 0
3 years ago
8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (
love history [14]

(1) acceleration, a = 4 m/s^{2}  (2) acceleration of 10 N, a_{1} = 1 m/s^{2} and acceleration of 30 N, a_{2} = 3 m/s^{2}

Explanation:

  • Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
  • Let a_{1} be the acceleration for force 10 N, to find acceleration rearrange the equation to a = \frac{F}{m}. When we substitute 10 N force and 10 kg mass of the box in the equation. We will get a_{1} = 1 m/s^{2}
  • Let a_{2}  be the acceleration for force 30 N, to find acceleration rearrange the equation to F = \frac{F}{m}. When we substitute 30 N force and 10 kg mass of the box in the equation. We will get a_{2} = 3 m/s^{2}
  • To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/s^{2}
3 0
2 years ago
An object is sitting on the floor. A 22.4 N force is pulling the object to the right and an 11 N force is pulling the object to
Nimfa-mama [501]

answer = 33.4 net force.

5 0
2 years ago
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