If you press on your arm force is applied work done is if it moves.
One answer could be if I was to press my hand on a table.
Have a great day!
<span>
Of course. Wind is air in motion, and the gases in air are composed of
all the usual familiar stuff ... atoms, molecules, mass, etc. That's how
the wind moves things ... it has momentum and kinetic energy, which
get transferred to the things that move in the wind.</span>
Answer:
a)11.25 J
b)Number of revolution = 1
Explanation:
Given that
Radius ,r= 0.8 m
m= 0.3 kg
Initial speed ,u= 10 m/s
final speed ,v= 5 m/s
a)
Initial energy
KEi= 15 J
Final kinetic energy
KEf=3.75 J
The energy transformed from mechanical to internal = 15 - 3.75 J = 11.25 J
b)
The minimum value to complete the circular arc
Now by putting the values
V= 2.82 m/s
So kinetic energy KE
KE=1.19 J
ΔKE= KEi - KE
ΔKE= 15- 1.19 J
ΔKE=13.80 J
The minimum energy required to complete 2 revolutions = 2 x 11.25 J
= 22.5 J
Here 22.5 J is greater than 13.8 J.So the particle will complete only one revolution.
Number of revolution = 1
Answer:
C. Technician B
Explanation:
Excessive Galvanic activity:
To check for excessive galvanic activity, voltmeter is used to check the coolant. If the voltmeter is giving a reading greater than 0.5 V, there is excessive galvanic activity. Excessive galvanic activity is solved by flushing the coolant fluid from engine and refiling it.
Electrolysis problem:
When the system is not properly ground, the cooling system accepts stray current and the coolant becomes an electrolyte which might eat up the radiator. To test for excessive electrolysis, start the engine and turn on all electrical accessories, if the reading is more than 0.5 V, there is electrolysis problem. Ground wires and connections should be checked at this point to stop stray current.
In our case, the first reading is 0.2 V(engine turned off) which is normal and there is no excessive galvanic activity. This means that Technician A is not correct. The second reading is 0.8 V when the engine and all electrical accessories are turned on. This reading is greater than 0.5 V which means there is an electrolysis problem. This means that Technician B is correct and ground wires and connections should be inspected and repaired.
Answer:
ξ = 0.00845020162 V or 8.4 mV
Explanation:
Magnetic flux measures the total magnetic field that passes through a known area. Magnetic flux describe the effect of magnetic field in a given area. Mathematically,
magnetic flux (Ф) = BA cos ∅
where
A = test area
B = magnetic field
before the flip
Ф = Bπr²N
N = number of turn
magnitude of induced emf = N |ΔФ/Δt|
ξ = 2Nπr²B/dt
ξ = 2 × 22 × π × (1.02/2)² × 0.000047/0.2
ξ = 44 × π × 0.51² × 0.000047/0.2
ξ = 44 × π × 0.2601 × 0.000047/0.2
ξ = 0.0005378868 × 3.142/0.2
ξ = 0.00169004032/0.2
ξ = 0.00845020162 V or 8.4 mV
