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Gelneren [198K]
3 years ago
12

Pulsars A. spin very rapidly when they're young. B. are the cause of gamma-ray bursts. C. spin very slowly when they're young, a

nd gradually spin faster as they age. D. generally form from 25-solar-mass stars. E. emit radio in all directions.
Physics
1 answer:
patriot [66]3 years ago
5 0

Answer: A. spin very rapidly when they're young.

Explanation:

A pulsar (pulsating star) is a neutron star that emits very intense jets of electromagnetic radiation in the range of radio waves, X-rays or gamma rays, at short and periodic intervals due to its intense magnetic field that induces this emission.  

One of its main charateristics is its  rapidly rotation (spin) when this star is young. So, as the star spins, beams of radio radiation from it sweep through space. If one of these beams points toward the Earth, we observe a <u>pulse</u>.  

This is possible when the magnetic pole of the star "points" to the Earth and then stops pointing a thousandth of a second later due to the fast rotation of the star, appearing again when the same pole returns to point towards Earth.  

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Answer:

its B

Explanation:

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3 years ago
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Consider two points in an electric field. The potential at point 1, V1, is 33 V. The potential at point 2, V2, is 175 V. An elec
Mnenie [13.5K]

Answer:

ΔU  = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J

Explanation:

Since the electric potential at point 1 is V₁ = 33 V and the electric potential at point 2 is V₂ = 175 V, when the electron is accelerated from point 1 to point 2, there is a change in electric potential ΔV which is given by ΔV = V₂ - V₁.

Substituting the values of the variables into the equation, we have

ΔV = V₂ - V₁.

ΔV = 175 V - 33 V.

ΔV = 142 V

The change in electric potential energy ΔU = eΔV = e(V₂ - V₁) where e = electron charge = -1.602 × 10⁻¹⁹ C and ΔV = electric potential change from point 1 to point 2 = 142 V.

So, substituting the values of the variables into the equation, we have

ΔU = eΔV

ΔU = eΔV

ΔU = -1.602 × 10⁻¹⁹ C × 142 V

ΔU = -227.484 × 10⁻¹⁹ J

ΔU = -2.27484 × 10⁻²¹ J

ΔU ≅ -2.275 × 10⁻²¹ J

So, the required equation for the electric potential energy change is

ΔU  = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J

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2 years ago
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3 years ago
what is the net force on an object that is experiencing a force of 25 N north, a force of 25 N south, a force of 50 N to the eas
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ipn [44]

Answer:

If you pull a permanent magnet rapidly away from a tank circuit, what is likely to happen in that circuit?

Charge will oscillate in the tank's capacitor and inductor.

Explanation:

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