Answer:
Explanation:
Equation of reactions:
1. N2 (g) + 2O2(g) --> 2NO2 (g)
ΔH = 66.4 kJ
2. 2NO (g) + O2 (g) --> 2NO2 (g)
ΔH = -114.2 kJ
Final equation
N2 (g) + O2 (g) --> 2NO (g)
Inverting equation 2, note that the ΔH will now be positive.
3. 2NO2 (g) --> 2NO (g) + O2 (g)
ΔH = 114.2 kJ
Adding equation 1 and 3 together as well as their enthalpies,
N2 (g) + 2O2(g) --> 2NO2 (g)
2NO2 (g) --> 2NO (g) + O2 (g)
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N2 (g) + O2 (g) = 2NO (g)
ΔH = 114.2 kJ + 66.4 kJ
= 180.6 kJ
N2 (g) + O2 (g) --> 2NO (g)
ΔH = 180.6 kJ