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BartSMP [9]
3 years ago
7

N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ 2NO (g) + O2 (g) = 2NO2 (g) ΔH = -114.2 kJ the enthalpy of the reaction of the nitrogen

to produce nitric oxide N2 (g) + O2 (g) = 2NO (g) is __________ kJ.
Chemistry
2 answers:
OLga [1]3 years ago
8 0

Answer:

Explanation:

Equation of reactions:

1. N2 (g) + 2O2(g) --> 2NO2 (g)

ΔH = 66.4 kJ

2. 2NO (g) + O2 (g) --> 2NO2 (g)

ΔH = -114.2 kJ

Final equation

N2 (g) + O2 (g) --> 2NO (g)

Inverting equation 2, note that the ΔH will now be positive.

3. 2NO2 (g) --> 2NO (g) + O2 (g)

ΔH = 114.2 kJ

Adding equation 1 and 3 together as well as their enthalpies,

N2 (g) + 2O2(g) --> 2NO2 (g)

2NO2 (g) --> 2NO (g) + O2 (g)

---------------------------------------

N2 (g) + O2 (g) = 2NO (g)

ΔH = 114.2 kJ + 66.4 kJ

= 180.6 kJ

N2 (g) + O2 (g) --> 2NO (g)

ΔH = 180.6 kJ

RSB [31]3 years ago
3 0

Answer:

ΔH  = 180.6 kJ

Explanation:

Given that:

N2 (g) + 2O2(g) = 2NO2 (g)           ΔH = 66.4 kJ

<u>2NO (g) + O2 (g) = 2NO2 (g)         ΔH = -114.2 kJ                     </u>

N2 (g) + O2 (g) = 2NO (g)              ΔH  = ????

The subtraction of both equations would yield the unknown ΔH , therefore:

ΔH = 66.4 - ( - 114.2 kJ)

ΔH  = 180.6 kJ

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Answer:

0.175mol

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Mole of a substance can be calculated using the formula as follows:

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A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to . He'll do this by add
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It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:

" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "

Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.

To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂

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