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Darina [25.2K]
3 years ago
15

How many grams of nickel (+2) are required to replace all of the silver when 15.55 grams of AgNO3 are present?

Chemistry
1 answer:
Karolina [17]3 years ago
8 0

2AgNO3 + Ni2+  = Ni(NO3)2 + 2Ag<span>+</span>

From the reaction, it can be seen that AgNO3 and Ni2+ has following amount of substance relationshep:

n(AgNO3):n(Ni)=2:1

From the relationshep we can determinate requred moles of Ni2+:

n(AgNO3)=m/M= 15.5/169.87=0.09 moles

So, n (Ni)=n(AgNO3)/2=0.045 moles

Finaly needed mass of Ni2+ is:

m(Ni2+)=nxM=0,045x58.7=2.64g

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Gabriella weighs 450 N. She climbs a flight of stairs to a height of 3 m. It takes her 5 seconds. How much work does Gabriella d
Flura [38]

The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.

W = Fd

W = (450N) (3m)

W = 1350J

The answer is letter C.

6 0
3 years ago
1) A light bulb takes in 30 of energy per second. It transfers 3j as use
natta225 [31]

Answer:

\boxed{\text{10 \%}}

Explanation:

The formula for efficiency is  

\begin{array}{rcl}\text{Efficiency} & = & \dfrac{\text{useful energy out}}{\text{energy in}} \times 100 \,\% \\\\\eta & = & \dfrac{w_{\text{out}}}{w_{\text{in}} } \times 100 \,\%\\\end{array}

Data:

Useful energy =  3 J

Energy input  = 30 J

Calculation:

\begin{array}{rcl}\eta & = & \dfrac{\text{3 J}}{\text{30 J}} \times 100 \,\%\\\\\eta & = & 10 \, \%\\\end{array}\\\text{ The efficiency is }\boxed{\textbf{10 \%}}

8 0
3 years ago
Where do the sun rays hit Earth's surface nearly at right angles ​
hoa [83]

Answer:

The Sun Ray's hit earths surface at Earths Equator

8 0
2 years ago
A binding protein binds to a ligand l with a kd of 400 nm what is the concentration of ligand when y is 0.25
vampirchik [111]

Answer:

The answer is 7600 nm.

Explanation:

As, Y = 0.25 = [ L ÷ (400 + (L)]

0.95 x 400 + 0.25 [ L] = [ L ]

380.25  = [ L ] - 0.95 [ L ]

              = 0.05 [L]

[L] = 380 ÷ 0.05 = 7600nm

6 0
3 years ago
The vapor pressure of water at 25.0°C is 23.8 torr. Determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
mrs_skeptik [129]

According to Raoult's law the relative lowering of vapour pressure of a solution made by dissolving non volatile solute is equal to the mole fraction of the non volatile solute dissolved.

the relative lowering of vapour pressure is the ratio of lowering of vapour pressure and vapour pressure of pure solvent

\frac{p^{0-}p}{p^{0}}=x_{B}

Where

xB = mole fraction of solute=?

p^{0}=23.8torr

p = 22.8 torr

x_{B}=\frac{23.8-22.8}{23.8}=0.042

mole fraction is ratio of moles of solute and total moles of solute and solvent

moles of solvent = mass / molar mass = 500 /18 = 27.78 moles

putting the values

molefraction=\frac{molessolute}{molesolute+molessolvent}

0.042=\frac{molessolute}{27.78+molessolute}

1.167+0.042(molesolute)=molessolute

molessolute=1.218

mass of glucose = moles X molar mass = 1.218 X 180 = 219.24 grams



3 0
3 years ago
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