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Aneli [31]
3 years ago
12

En una progresion geometrica el primer termino es 4 ¿ cual debe de ser la razon para que la suma de sus infinitos sea 5?

Mathematics
1 answer:
dem82 [27]3 years ago
3 0

Respuesta:

La proporción común del término puede ser 1/5

Explicación paso a paso:

La fórmula para calcular la suma al infinito de una secuencia geométrica se expresa como:

Sinfty = a / 1-r

Dado

Sinfty = 5

Primer término a = 4

Requerido

Razón común r

Sustituir

5 = 4/1-r

5 (1-r) = 4

5-5r = 4

-5r = 4-5

-5r = -1

r = 1/5

Esto significa que la razón común debe ser 1/5 para que la suma hasta el infinito sea 5

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Which function below is the inverse of f(x)= 3x+5/7
valkas [14]

Answer:

\huge\boxed{f^{-1}(x) = \frac{7x-5}{3}}

Step-by-step explanation:

Given the function:

f(x) = \frac{3x+5}{7}

Put f(x) = y

y = \frac{3x+5}{7}

Interchange x and y

x = \frac{3y+5}{7}

Solve for y

x = \frac{3y+5}{7}

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<u>OR</u>

y = \frac{7x-5}{3}

Put y = f^{-1}(x)

So,

f^{-1}(x) = \frac{7x-5}{3}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
5 0
4 years ago
.
Andreyy89

Answer:

B

Step-by-step explanation:

its just gotta be b because yk it makes sense when you solve it.

3 0
4 years ago
Please help I will reward brainly !!!
3241004551 [841]
Hello there!

I hope you are having a good day!


Your answer would be c because it is adding by 3 each time, making it arithmetic.


Hope I helped!

Let me know if you need anything else!

~Zoe
6 0
3 years ago
Read 2 more answers
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