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katrin2010 [14]
3 years ago
10

Rings are a characteristic of

Chemistry
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

physical

Explanation:

if it is asking to determine what it is a sign of or how to identify that characteristic it would be a physical.

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By atomic number?

Explanation:

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8 0
3 years ago
Equal volumes of hydrogen and helium gas are at the same pressure. The atomic mass of helium is four times that of hydrogen. If
OverLord2011 [107]

Answer:

The ratio of the temperature of helium to that of hydrogen gas is 2:1.

Explanation:

Atomic mass of hydrogen = M

Temperature of hydrogen gas =T

Pressure of the hydrogen gas = P

Mass of the hydrogen gas = m

Moles of the hydrogen gas = n=\frac{m}{2M}

Volume of the hydrogen gas = V

Using an ideal gas equation:

PV=nRT=PV=\frac{mRT}{M}...(1)

Temperature of helium gas =T'

Pressure of the helium gas = P'= P

Mass of the helium gas = m' =m

Moles of the helium  gas = n'=\frac{m}{M'}=\frac{m}{4M}

Volume of the helium gas = V' = V

Using an ideal gas equation:

P'V'=n'RT'=\frac{mRT'}{4M}...(2)

Divide (2) by (1)

\frac{P'V'}{PV}=\frac{\frac{mRT'}{4M}}{\frac{mRT}{2M}}

\frac{T'}{T}=\frac{2}{1}

The ratio of the temperature of helium to that of hydrogen gas is 2:1.

7 0
3 years ago
A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

5 0
4 years ago
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