Answer: The answer is (C) 324 cubic cm.
Step-by-step explanation: As given in the question, given a solid oblique pyramid with a regular hexagonal base and area 54√3 cm². Also, the edge length of the base is 6cm and ∠BAC = 60°.
We are to find the volume of the pyramid.
The formula for finding the volume of a pyramid is given by
![V=\dfrac{1}{3}b\times h,](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7Db%5Ctimes%20h%2C)
where, 'b' is the base area and 'h' is the perpendicular height of the pyramid.
Here, b = 54√3 cm², h = ?
Now, from the right-angled triangle ABC, we have
![\dfrac{\textup{BC}}{\textup{AC}}=\tan 60^\circ\\\\\Rightarrow \dfrac{h}{6}=\sqrt 3\\\\\Rightarrow h=6\sqrt 3.](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextup%7BBC%7D%7D%7B%5Ctextup%7BAC%7D%7D%3D%5Ctan%2060%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7Bh%7D%7B6%7D%3D%5Csqrt%203%5C%5C%5C%5C%5CRightarrow%20h%3D6%5Csqrt%203.)
Therefore, the volume of the pyramid is
![V=\dfrac{1}{3}b\times h=\dfrac{1}{3}\times 54\sqrt 3\times 6\sqrt 3=324.](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7Db%5Ctimes%20h%3D%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%2054%5Csqrt%203%5Ctimes%206%5Csqrt%203%3D324.)
Thus, the required volume is
This makes (C) as the correct option.