C. chlorophyll
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Answer:

Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32 60
CH₃OH + CO ⟶ CH₃COOH
m/g: 160
(a) Moles of CH₃OH

(b) Moles of CH₃COOH

(c) Mass of CH₃COOH

Answer:
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Answer:
Explanation:
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Answer:
3.4g of Al
Explanation:
you would need to start with 3.4 g of Al