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erik [133]
2 years ago
6

An unknown has a chemical formula of C4H10O. When chromic acid was added to the unknown, it turned green. When the Lucas reagent

was added to a separate portion of the unknown, it turned cloudy in 5 minutes. When NaOH and KI/iodine was added to the unknown, a yellow precipitate formed. What is the structure of the unknown compound?
Chemistry
1 answer:
aalyn [17]2 years ago
6 0

Answer:

The structure of the unknown compound is 2-butanol.

Explanation:

Chromic acid reagent is the most efficient procedure for oxidizing secondary alcohols. Chromic acid in aqueous sulfuric acid and acetone solution is known as Jones reagent, which oxidizes primary and secondary alcohols to carboxylic acids and ketones, respectively.

Lucas reagent reacts with primary, secondary and tertiary alcohols with fairly predictable rates, and these rates can be used to distinguish between the three types of alcohols.  If the solution becomes cloudy in 3 to 5 minutes it indicates the presence of a secondary alcohol.

These two methods indicate the presence of a secondary alcohol, but the iodoform test indicates a specific structural unit.

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What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula is C2H3
iren [92.7K]
To find the molecular formula from the empirical formula, you need to find a multiple (x) that will give you the molar mass of the compound which in the question is 54 g/mol.

If C₂H₃ is the empirical formula
 molar mass of empirical formula = (12 × 2) + (1 × 3) g/mol
                                                     =  27 g/mol
let x = multiple
let molecular formula = C₂ₓ H₃ₓ

            multiple = molecular mass ÷ empirical mass
                         =  54 g/mol ÷  27 g/mol
                         =  2


If molecular formula = C₂ₓ H₃ₓ

then molecular formula = C₂₍₂₎H₃₍₂₎

                                      = <span>C₄H</span>₆

8 0
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