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tatuchka [14]
3 years ago
13

Mrs. Borunda has a sample of oxygen gas that occupies a volume of 600 L at 400 atm pressure. What will the pressure be if she in

creases the volume to
800 L?

300 atm

450 atm

540 atm

250 atm
Chemistry
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

P₂ = 300 atm

Explanation:

Given that,

Initial volume, V₁ = 600 L

Initial pressure, P₁ = 400 atm

We need to find the pressure if the volume is 800 L.

We know that the relation between pressure and volume is given by :

P\propto \dfrac{1}{V}\\\\\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{600\times 400}{800}\\\\P_2=300\ atm

So, the new pressure is equal to 300 atm.

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Rocks are solids composed of one or more minerals true or false
Yuki888 [10]
The answer is true
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8 0
3 years ago
two students are working together to build a birdhouse. Student 1 applies a force of 10 N to a wooden board in order to slide it
Ganezh [65]

Answer:

6

Explanation:

if there is 10n and the friction is 4n on the table then it is 6n.

i hope this helps you! :)

5 0
2 years ago
How do you solve this problem
ad-work [718]

Answer: Volume of gas in the stomach, V = 0.0318L or 31.8mL

Explanation:

The number of moles of oxygen will remain constant even though the liquid oxygen will undergo a change of state to gaseous inside the person's stomach due to an increase in temperature.

<em>Number of moles of oxygen gas = mass/molar mass</em>

molar mass of oxygen gas = 32 g/mol

mass of oxygen gas = density * volume

mass of oxygen gas = 1.149 g/ml * 0.035 ml

mass of oxygen gas = 0.040215 g

Number of moles of oxygen gas = 0.0402 g/(32 g/mol)

Number of moles of oxygen gas = 0.00125 moles

<em>Using the ideal gas equation, PV=nRT</em>

where P = 1.0 atm, V = ?, n = 0.00125 moles, R = 0.082 L*atm/K*mol, T = (37 + 273)K = 310 K

<em>V = nRT/P</em>

V = (0.00125moles) * (0.082 L*atm/K*mol) * (310 K) / 1 atm

V = 0.0318L or 31.8mL

3 0
3 years ago
You've made the hypothesis that the less rainfall a cactus plant gets, the taller it will grow, since cactuses like dry conditio
Leviafan [203]

A. the height of the cactus plants

Explanation:

The dependent variable in this experiment designed to test this hypothesis is the height of the cactus plants.

In a hypothesis statement, we can always deduce the dependent and independent variables.

  • Independent variables do not rely on other variables. They are usually the cause of the phenomenon observed in an experiment. In this experiment, it is the rainfall on the cactus plant.
  • Dependent variable is that variable that relies on the independent variable. It is usually the effect of changes in independent variable.
  • The height of the cactus plant depends on the amount of rainfall in an area.

learn more:

Controlled experiment brainly.com/question/1621519

#learnwithBrainly

5 0
3 years ago
Determine whether or not each ion contributes to water hardness.
Virty [35]

Answer: The ion that contribute to water hardness are:

--> a. Ca2+

--> b. (HCO)3^- and

--> c. Mg2+

While K+ DOES NOT contribute to water hardness.

Explanation:

WATER in chemistry is known as a universal solvent. This is so because it is polar in nature and dissolves most inorganic solutes and some polar organic solutes to form aqueous solutions. It is composed of elements such as hydrogen and oxygen in the combined ratio of 2:1.

Water is said to be HARD if it does not lather readily with soap. There are two types of water hardness:

--> Permanent hardness: This is mainly due to the presence of CALCIUM and MAGNESIUM ions in the form of soluble tetraoxosulphate(VI) and chlorides. These ions are removed by adding washing soda or caustic soda.

--> Temporary hardness: This is due to the presence of calcium HYDROGENTRIOXOCARBONATES. It can be removed by boiling and using slaked lime.

Therefore from the above given ions, Ca2+,(HCO)3^- and Mg2+ contributes to water hardness.

4 0
2 years ago
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