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3 years ago

Is honors math easy?

Mathematics

2 answers:

umka2103 [35]3 years ago

5 0

Answer:

Step-by-step explanation:

N76 [4]3 years ago

3 0

Answer:

Actually it is. Think of it as a standard math. It is not at all hard. AP MAth is very hard because it's a ton of stuff and a whole bunch of maybe even college assignments. I would know because i was one in honors but now in AP. Trust me when i ay that i fool around in clas and still get an A.

Step-by-step explanation:

You might be interested in

Whats the difference in 2/3 - 1/6

nasty-shy [4]

Answer:

2/3&1/6

2/3- 1/6

the LCM for 3 and 6 is 6

=(2x6)/(3x6) -(1x6)/(6x6)

=4/6-1/6

=(4-1)/6

find the difference

= 3/6

=1/2

2/3-1/6= 1/2

By using LCM method, 1/2 is the equivalent fraction by subtracting 1/6 from 2/3.

2/3&1/6

2/3- 1/6

cross multiply

2x6-1x3/3x6

simplify

12-3/18

=9/18

= 1/2

2/3-1/6 = 1/2

By using cross multiplication method, 1/2 is the difference between two fractions 2/3 and 1/6.

Step-by-step explanation:

hope that helps>3

7 0

2 years ago

Thank you for you help

Harrizon [31]

the first simple interest will be $1.73 more than the second one.

<h3>Which is the difference between the two interests?</h3>

The loan is of $575, and there are two options:

7 years at 4.5% or 8 years at 3.9%

Remember that the simple interest formula is:

SI = (P*R*T)/100

Where:

P = principal value.

R = rate (this is the percentage per year)

T = time, in years.

Then for the first option. the interest will be:

SI = ($575*4.5*7)/100 = $181.13

For the second option we will have the interest:

SI' =( $575*3.9*8)/100 = $179.4

The difference is:

$181.13 - $179.4 = $1.73

This means that the first simple interest will be $1.73 more than the second one.

If you want to learn more about simple interests:

brainly.com/question/20690803

#SPJ1

7 0

1 year ago

Explain how you could write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two dis

skad [1K]

The definition of quadratic function is given by:

 $(1) \ f(x)=ax^{2}+bx+c \\ \\ where \ a, b, c \ are \ real \ values$ 

So the problem asks for two conditions:

1. Write the quadratic function in factored form. 
2. The vertex has an x-coordinate of 3.

Then the equation (1) must be written as follows:

 $f(x)=(x-m)(x-n) \\ \\ where \ m \ and \ n \ are \ the \ roots$ 

To satisfy the two conditions:

$\frac{m+n}{2}=3$

So we are free to choose the value of one root, say:

$m=1$

Thus:

$n=6-1=5$

Finally, the answer is:

$f(x)=(x-1)(x-5)$

The graph of this function is shown in the figure below.