Even numbers can be divided into two equal groups while odd numbers cannot so every other number is an even number because it can be divided into two equal groups
8-(6+2)+4 is how you use those numbers to equal 4
Answer:
91
Step-by-step explanation:
Look at multiples of 7 and you’ll find 91.
91 dived by 3 is 30 with a remainder of 1.
91 divided by 5 is 18 with a remainder of 1.
91 divid by 7 is 13 with no remainder.
Answer:
Step-by-step explanation:
The wording on this is not the best. It sounds like the 1 zero has even multiplicity (that's because of where the modifier is). On top of that it has an odd power. You could try this. y =x*(x^2+1)^2
The problem is not with the power. It gives x^5. The problem is with the multiplicity of the one place where it crosses. (X^2 + 1) does factor, but it gives a complex root. I'm not sure that's allowed. However, it is the best I can do.
A= (b sin A)/ sinB
a= (15.8 sin29)/ sin36
a= 13.03 cm
