i think its a right tringle
3LiOH+Fe(NO3)3--›Fe(OH)3↓+3LiNO3
n(LiOH)=m/M=(25g)/(24g/mol)=1,0417mol
n(Fe(OH)3)=1/3n(LiOH)=0,3472mol
m(Fe(OH)3)=n*M=0,3472mol*107g/mol=37,15g
Answer is:
7.8 lb of 21% aluminum and 33.2 ib of <span>
42% aluminum.</span>
ω₁<span> = 21% ÷ 100% = 0.21.
ω</span>₂<span> = 42% ÷ 100% = 0.42.
ω</span>₃<span> = 38% ÷ 100% = 0.38.
</span>m₁ = ?.
m₂<span> = ?.
</span>m₃ = m₁ + m₂<span>.
</span>m₃ = 41 pounds.
m₁ = 41 lb - m₂<span>.
ω</span>₁ · m₁ + ω₂ ·m₂ = ω₃ · m₃.
0.21 · (41 lb -
m₂) + 0.42 · m₂ = 0.38 · 41 lb.
8.61 lb - 0.21m₂ + 0.42m₂ = 15.58 lb.
0.21m₂ = 6.97 lb.
m₂ = 6.97 lb ÷ 0.21.
m₂ = 33.2 lb.
m₁ = 41 lb - 33.2 lb.
m₁<span> = 7.8 lb.</span>
Answer:
Initial rate of reaction is 
.
Explanation:
It is a second order reaction.
Initial rate of reaction = ![k[O_{3}]_{0}[NO]_{0}](https://tex.z-dn.net/?f=k%5BO_%7B3%7D%5D_%7B0%7D%5BNO%5D_%7B0%7D)
, where k is rate constant, ![[O_{3}]_{0}](https://tex.z-dn.net/?f=%5BO_%7B3%7D%5D_%7B0%7D)
is the initial concentration of 
and ![[NO]_{0}](https://tex.z-dn.net/?f=%5BNO%5D_%7B0%7D)
is the initial concentration of NO.
Here, k = 
, ![[O_{3}]_{0}=5.84\times 10^{-6}M](https://tex.z-dn.net/?f=%5BO_%7B3%7D%5D_%7B0%7D%3D5.84%5Ctimes%2010%5E%7B-6%7DM)
and ![[NO]_{0}=8.65\times 10^{-5}M](https://tex.z-dn.net/?f=%5BNO%5D_%7B0%7D%3D8.65%5Ctimes%2010%5E%7B-5%7DM)
So, initial rate of reaction = 
=
So, initial rate of reaction is
iron is a metal and sulfur is a non-metal and both are in the periodic table which means they are elements. Together they can form a compound with an ionic bond. and can be mixed to form a mixture.
