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trapecia [35]
3 years ago
10

The half-life of plutonium-239 is 24300. If a nuclear bomb released 8kg of this isotope, how many years would pass before the am

ount is reduced to 1kg?
Chemistry
1 answer:
Aneli [31]3 years ago
3 0

Answer:

= 72900 years

Explanation:

  • The half-life is the time taken by a radioactive material to decay by half the original amount.
  • The half-life of plutonium-239 is 24300 years which means it takes 24300 years to decay by half the original amount.

To calculate the time taken for a mass of 8 kg to decay to 1 kg we use;

New mass = Original mass x (1/2) ^n, where n is the number of half-lives

Therefore;

1 kg = 8 kg × (1/2)^n

1/8 = (1/2)^n

solving for n;

n =3

Therefore;

Time = 3 × 24300 years

          = 72900 years

It will, therefore, take 72900 years for 8 kg of plutonium-239 to decay to 1 kg.

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3 years ago
How many moles of gold are there in 3.73 x 10^24 atoms of gold?
BARSIC [14]

Answer:

6.2moles of Gold

Explanation:

To solve this problem, we are going to use the mole concept approach.

 Given that;

  Number of atoms of gold is 3.73 x 10²⁴ atoms

Now;

  In 1 mole of any substance, we have 6.02 x 10²³ atoms;

   So;

  If there  6.02 x 10²³ atoms in  1 mole of any substance;

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4 0
2 years ago
If the enantiomeric excess of a mixture is 75%, what are the % compositions of the major and minor enantiomer?
Maru [420]

Let us say that R is the major enantiomer, while S is the minor enantiomer, therefore the formula for enantiomeric excess (ee) is:

ee = (R – S) * 100%

 

Let us further say that the fraction of R is x (R = x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:

75 = (x – (1 – x)) * 100

75 = 100 x – 100 + 100 x

200 x = 175

x = 0.875

 

Summary of answers:

R = major enantiomer = 0.875 or 87.5%

<span>S = minor enantiomer = (1 – 0.875) = 0.125 or 12.5%</span>

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