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gayaneshka [121]
3 years ago
6

A machine cuts 25 circuit boards every 5 minutes. What is the unit rate of production for the machine?

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

25 divided by 5 = 5, so the unit rate is 5 circuit boards every minute.

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How many minutes is it before 12 noon if 68 minutes ago it was three times as many minutes past 10 a.m.?​
umka21 [38]
If 68 minutes ago it (then) was three times as many minutes past 10 am (now)

x + 68 = 3 ×
×
(120 - x) →
→
x = 73 min
… if 68 minutes ago it (now) was three times as many minutes past 10 am (then)

x = 3 ×
×
[120 - (x + 68)] →
→
x = 39 min
… if 68 minutes ago it (then) was three times as many minutes past 10 am (then)

x + 68 = 3 ×
×
[120 - (x + 68)] →
→
x = 22 min
7 0
3 years ago
Verify which of the following are identities.
-Dominant- [34]

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot    \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

8\sec(\theta)=8\csc(\theta)

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

3 0
3 years ago
Which similarity statement describe the relationship between the two triangle? Check all that apply
anzhelika [568]

Answer:

If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar

8 0
3 years ago
An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is
Ganezh [65]

Answer:

(a) 0.20

(b) 31%

(c) 2.52 seconds

Step-by-step explanation:

The random variable <em>Y</em> models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters <em>a</em> = 1 and <em>b</em> = 5.

So, Y\sim Unif(1,5)

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

\text{Area under the density curve}=\text{length}\times \text{height}

                                          1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31

Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.

(c)

Compute the 38th percentile as follows:

P(Y

Thus, the 38th percentile is 2.52 seconds.

4 0
3 years ago
1. It is a three-digit whole number.
taurus [48]

Answer:

660

Step-by-step explanation:

4x5x11x3 = 660

8 0
3 years ago
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