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choli [55]
3 years ago
15

If you help me with the correct answer I will give you the brainlist

Physics
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

1. A force is a push or pull upon an object resulting from the object's interaction with another object.  

Explanation:

You might be interested in
You've learned about simple circuits and resistors at this point. So, let's talk about how we can power different circuits. Supp
DIA [1.3K]

Answer:

Explanation:

Total resistance of 2 bulb in series

= 100 +100 = 200 ohm

current in each bulb

= 9/200 = .045 A

In case of parallel combination of bulb

total resistance

= 100 x 100 / (100+100)

50 ohm

current in the main circuit

= 9 / 50 A

current in each bulb

= 9 / (2 x 50)

.09

So in the second case current is more , hence heat generated too will be more . So brightness too will be more.

First set (  in  series ) will be dimmer.

3 0
3 years ago
A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t
JulijaS [17]

Answer:

Dy = 111.66 [m]

t  = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

v_{f} = v_{o} - (g*t)\\

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

Dy=v_{o} *t+\frac{1}{2}*g*t

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

5 0
3 years ago
A speed truck locks it’s brakes and it skids to a stop. If the truck’s total mass were doubled, it’s skidding distance would be?
Gnom [1K]

Answer:

The skidding distance would be doubled

Explanation:

When the truck applies the brakes and slows down, its motion is a uniformly accelerated motion, so its skidding distance can be found by using the suvat equation

v^2-u^2=2as

where

v = 0 is the final velocity (zero since the truck comes to a stop)

u is the initial velocity

a is the acceleration

s is the skidding distance

The acceleration can also be written as

a=\frac{F}{m}

where F is the force applied by the brakes and m the mass of the truck. Substituting into the previous equation,

-u^2 = 2\frac{F}{m}s\\s = -\frac{mu^2}{2F}

We see that the skidding distance is proportional to the mass: therefore, if the mass of the truck is doubled, the skidding distance will double as well.

5 0
3 years ago
How can the center of gravity of a rigid body be determined?
ipn [44]
To calculate the center of gravity, divide total weight distance moment by total mass of the system. Thus, the center of gravity is 13 meter from left-hand side.
5 0
3 years ago
What happens to the kinetic energy of a snowball as it rolls across the lawn and gains mass.
LiRa [457]

If the ground is level, then the snowball can never have
any more kinetic energy than it hand when it left your hand.

If more mass sticks to it as it makes its way across the lawn,
then it must slow down, so that its

                 KE = (1/2) (present mass) (present speed)²

never exceeds the KE you gave it when you tossed it.

And we're not even talking yet about all the energy it loses
by scraping through the snow and mashing down the blades
of grass in its path.

5 0
4 years ago
Read 2 more answers
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