Answer:
Explanation:
Total resistance of 2 bulb in series
= 100 +100 = 200 ohm
current in each bulb
= 9/200 = .045 A
In case of parallel combination of bulb
total resistance
= 100 x 100 / (100+100)
50 ohm
current in the main circuit
= 9 / 50 A
current in each bulb
= 9 / (2 x 50)
.09
So in the second case current is more , hence heat generated too will be more . So brightness too will be more.
First set ( in series ) will be dimmer.
Answer:
Dy = 111.66 [m]
t = 3.5 [s]
Explanation:
To solve this problem we must use the equations of kinematics.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 27 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 3.5 [s]
Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction
Vf = 27 - (9,81*3,5)
Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)
To find how high the snowball was we must use the following equation:

Dy = (27*3.5) + (0.5*9.81*3.5)
Dy = 94.5 + (17.16)
Dy = 111.66 [m]
Answer:
The skidding distance would be doubled
Explanation:
When the truck applies the brakes and slows down, its motion is a uniformly accelerated motion, so its skidding distance can be found by using the suvat equation

where
v = 0 is the final velocity (zero since the truck comes to a stop)
u is the initial velocity
a is the acceleration
s is the skidding distance
The acceleration can also be written as

where F is the force applied by the brakes and m the mass of the truck. Substituting into the previous equation,

We see that the skidding distance is proportional to the mass: therefore, if the mass of the truck is doubled, the skidding distance will double as well.
To calculate the center of gravity, divide total weight distance moment by total mass of the system. Thus, the center of gravity is 13 meter from left-hand side.
If the ground is level, then the snowball can never have
any more kinetic energy than it hand when it left your hand.
If more mass sticks to it as it makes its way across the lawn,
then it must slow down, so that its
KE = (1/2) (present mass) (present speed)²
never exceeds the KE you gave it when you tossed it.
And we're not even talking yet about all the energy it loses
by scraping through the snow and mashing down the blades
of grass in its path.