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3 years ago

What is kinematics????explain briefly!!!!!

Physics

2 answers:

polet [3.4K]3 years ago

7 0

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

Explanation:

hope it helps!

Marysya12 [62]3 years ago

3 0

Answer:

i have only this much information

sry

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A traveling electromagnetic wave in a vacuum has an electric field amplitude of 50.9 V/m. Calculate the intensity ???? of this w

Sliva [168]

Answer:

3.44 W/m²

1.134 J

Explanation:

E₀ = Intensity of electric field = 50.9 V/m

I = Intensity of electromagnetic wave

Intensity of electromagnetic wave is given as

I = (0.5) ε₀ E₀² c

I = (0.5) (8.85 x 10⁻¹²) (50.9)² (3 x 10⁸)

I = 3.44 W/m²

A = Area = 0.0277 m²

t = time interval = 11.9 s

Amount of energy is given as

U = I A t

U = (3.44) (0.0277) (11.9)

U = 1.134 J

5 0

3 years ago

Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl

melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

$Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar$

The boundary layer thickness is equal to:

$\delta=\frac{4.91*1}{Re^{0.5} } =\frac{4.91*1}{246507^{0.5} } =0.0098$ ft

The shear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{1} )(246507)^{0.5} =0.012$

b) If the railing edge is 2 ft, the Reynold number is:

$Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar$

The boundary layer is equal to:

$\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft$

The sear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{2} )(493015.6^{0.5} )=0.0082$

c) The drag coefficient is equal to:

$C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019$

The friction drag is equal to:

$F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf$

7 0

3 years ago

Imagine you use Nitrogen as your gas. If you have the cold side as cold as you can without liquefying it (78 K), and run the hot

alina1380 [7]

Answer:

The efficiency of a Stirling engine is 74%

Explanation:

Given:

Temperature of gas when it is cold $T_{1} = 78$ K

Temperature of gas when it is hot $T_{2} = 300$ K

The efficiency of a stirling engine,

$\eta =1 - \frac{T_{1} }{T_{2} }$

$\eta = 1- \frac{78}{300}$

$\eta = 1-0.26$

$\eta = 0.74$

∴ $\eta = 74 \%$

Therefore, the efficiency of a Stirling engine is 74%

5 0

3 years ago

A 250 kg engine block is being dragged across the pavement by a sturdy chain with a tension force of 10,000 N, as seen in the fr

Musya8 [376]

Answer: B

Explanation:

The friction force is less than the tension force

4 0

3 years ago

Why must the lamina swing freely in physics

kirill115 [55]

Answer:

Unless the lamina is able to move freely under the influence of gravity, you do not know where to draw that line.

Explanation:

3 0

3 years ago

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What is kinematics????explain briefly!!!!! ​

What is kinematics????explain briefly!!!!!