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Alexus [3.1K]
3 years ago
8

What is the of 0.068 M of OH^ - ion?

Chemistry
1 answer:
Marina CMI [18]3 years ago
4 0

Answer:

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Explanation:

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Directions: Fill in the blanks to complete the idea. 1. Constellations are group of that form pattems in the night sky 2. Ursa M
siniylev [52]

1. Constellations are group of <u>stars</u> that form pattems in the night sky

2. Ursa Major, Cassiopeia, and Orion are some common <u>constellations</u><u>.</u>

3. Stars are used to tell <u>directions</u> and time, predict weather, and to serve as birth sign.

8 0
3 years ago
Enthalpies of reaction calculated from bond energies and from enthalpies of formation are often, but not always, close to each o
jolli1 [7]

The enthalpy change in a reaction is given by-

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

This can be expressed in terms of bond energy as-

ΔH°rxn = BEreactants - BEproducts

Therefore, the calculated bond energy according to the above equation will be-

ΔH°rxn = [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) ] - [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H)  = 0 kJ/mol

<h3>What is enthalpy change?</h3>

Enthalpy change is a measure of the energy emitted or consumed in a reaction. This can be determined using the following equation which involves standard enthalpy of reactant and product formation:

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

<h3>What is bond energy?</h3>

Bond energy is defined as the amount of energy needed to dissociate a mole of molecules into their individual atoms.

Learn more about the Enthalpy Change here:

brainly.com/question/14047927

#SPJ4

6 0
2 years ago
A solution of LiCl in water is 20.0 wt% LiCl. What is the mole fraction of LiCl?0.09600.4720.1064.44
Tresset [83]

Answer:

mole fraction of LiCl = 0.096

Explanation:

Weight percentage -

weight percentage of A is given as , the weight of the substance A by weight of the total solution multiplied by 100 .  

i.e.

weight % A = weight of A / weight of solution * 100

GIven ,

20.0 wt% LiCl

Now ,

Assuming weight of solution = 100 g ,  

weight if LiCl = 20.0 g

Since ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

molar mass of LiCl = 42.39  g/mol

moles of LiCl = mass / molar mass  = 20.0 g  / 42.39  g/mol = 0.472  mol

Since , solution = 100 g ,

and ,

Solution = solute + solvent

100g  = 20g  + solvent

Solvent = 80 g

mass of water = 80 g

water molecular mass = 18 g/mol

moles of water = 80g / 18 g/mol = 4.44 mol  

Mole fraction -

It is the ratio of the moles of one of the component of the solution by the mole of the solution .

Total moles of the solution = moles of the solute + moles of solvent

Total moles of the solution  = 0.472 mol  + 4.44 mol = 4.92  mol

Now ,

mole fraction of LiCl = moles of LiCl / total moles  = 0.472 mol / 4.92

mole fraction of LiCl = 0.096

3 0
3 years ago
what is a measure of the amount of matter in an object while what is a measure of the force of gravity acting on an object
masha68 [24]
A measure for the amount of matter in an object would be grams or kilograms.
the measure of the force of gravity acting on an object would be newtons.

the amount of matter in an object is called mass.
the force of gravity acting upon an object would be called weight.
7 0
3 years ago
12.39 HBr can be added to alkenes in either the absence or presence of peroxides (producing either the Markovnikov or the anti-M
Alex777 [14]

Answer:

See explanation and image attached

Explanation:

The reaction of HBr with 1-butene is an addition reaction. The HBr adds across the double bond to yield a saturated halogenoalkane.

In the absence of peroxides, the reaction proceeds in accordance with Markovnikov rule which states that;''the negative part of the addendum, is attached to the carbon atom with the least number of hydrogen atoms attached.'' This occurs in the first reaction shown in the image.

In the presence of peroxides, the reaction proceeds in an anti-Markovnikov manner to yield the product shown in the second reaction.

4 0
3 years ago
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