The Ksp of AgOH will be 1.98×10⁻⁸
According to the question,
The chemical reaction is:
AgOH (aq) + HCl (aq) ---> AgCl (s) + H₂O (aq)
Now, acc. to the formula:
C₁V₁ = C₂V₂
(AgOH) (HCl)
By substituting the values, we get:
C₁ x 250 ml = 0.0136 x 2.60 ml
C₁ = 0.000141
Now:
AgOH → Ag⁺(s) + OH⁻(s)
Hence,
Ksp will be:
= s²
= (0.000141)²
= 1.98x10⁻⁸
<h3><u>The value of Ksp(Solubility product constant)</u></h3>
When a chemical substance in the solid form is in chemical equilibrium with a solution of that molecule, a solubility equilibrium is a sort of dynamic equilibrium that develops. The solid may dissolve chemically reacting with another component of the solution, such as acid or alkali, or dissolving unaltered.
To know more about solubility constant, refer to:
brainly.com/question/1419865
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Answer:
Explanation:
Hello!
In this case, since this a reaction in which the oxidation state of the metals is changing, we need to apply a redox method for which:
Thus, the result is:
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If an atom is neutrally charged, then it has the same number of protons and electrones. When the atom loses one or more electrones, the protons are more than the electrones and the atom becomes a positively charged ion.
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Using Avogadro's number is possible to calculate the number of moles
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