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timama [110]
2 years ago
12

A standard drink is a unit of measurement. in the united states, a standard drink contains 0.6 fluid ounces of alcohol.which of

these drinks represents a standard drink?
Physics
1 answer:
lora16 [44]2 years ago
6 0

The example of an alcohol that represents standard drink is 1.5 oz liquor.

<h3>What is standard drink?</h3>

A standard drink is a measure of alcohol consumption representing a hypothetical beverage which contains a fixed amount of pure alcohol.

A standard drink is also a unit of measurement.

In the United States, a standard drink contains 0.6 fluid ounces of alcohol.

Thus, it is the amount of any beverage that contains about 14 grams/0.6 oz of pure alcohol.

Examples of standard drinks:

  • 12 oz beer/hard seltzer,
  • 5 oz wine,
  • 1.5 oz liquor (like vodka or rum)

Thus, the example of an alcohol that represents standard drink is 1.5 oz liquor.

Learn more about standard drinks here: brainly.com/question/17645986

#SPJ1

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What is the speed of a transverse wave in a rope of length 2.00 m and mass 60.0 g under a tension of 500 n?
drek231 [11]

The formula we can use in this case would be:

v = sqrt (T / (m / l))

Where,

v = is the velocity of the transverse wave = unknown (?)

T = is the tension on the rope = 500 N

m = is the mass of the rope = 60.0 g = 0.06 kg

 l = is the length of the rope = 2.00 m

Substituting the given values into the equation to search for the speed v:
v = sqrt (500 N/(0.06 kg /2 m)) 
v = sqrt (500 * 2 / 0.06) 
v = sqrt (16,666.67) 
<span>v = 129.10 m/s</span>

7 0
3 years ago
Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.
Tresset [83]

Answer:

a) transparent

b) transparent

c) opaque

Explanation:

In the first one, the light rays go completely through, so it is transparent.

The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.

Last one, the light rays are reflecting off the surface so it's opaque.

Please feel free to correct me if I'm wrong. This is just my understanding

6 0
3 years ago
Read 2 more answers
the goat weighs 900 N and is 1 meter from the fulcrum. The strongman pulls down on the lever 3 meters from the fulcrum. What is
garik1379 [7]

Answer: The smallest effort = 300N

Explanation:

Using one of the condition for the attainment of equilibrium:

Clockwise moment = anticlockwise moments

900 × 1 = 3 × M

Where M = the weight of the strong man

3M = 900

M = 900/3 = 300N

Therefore, 300N is the smallest effort that the strongman can use to lift the goat

6 0
3 years ago
A baseball is thrown 50.0m in 3.0s, what is the average speed of the baseball? Calculated answer is 16.666667! What is the corre
castortr0y [4]

Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \frac{distance }{time}

Insert the parameters and solve;

  Average speed  = \frac{50}{3}   = 16.66667m/s  = 20m/s

5 0
3 years ago
At what altitude h above the north pole is the weight of an object reduced to 67% of its earth-surface value? Assume a spherical
lara31 [8.8K]

Answer:

The answer to the question is

At an altitude of 1413 km or 1.222·R above the north pole the weight of an object reduced to 67% of its earth-surface value

Explanation:

We make use of the gravitational formula as follows

F = G\frac{m_{1} m_{2} }{R^{2} }  where

m₁ = mass of the object

m₂ = mass of the earth

d = distance between the two objects and

G = gravitational constant

if at the altitude the weight is reduced to 67 % of its weight on earth then

with all other variables remaining constant, we have

67% F = G\frac{m_{1} m_{2} }{R_{2} ^{2} } =0.67× G×\frac{m_{1} m_{2} }{R_{1} ^{2} }

cancelleing like ternss from  both sides we have

1/R₂² =0.67/R₁² or r₁²/R₂² =0.67 and R₁/R₂ = 0.8185

or R₂ = R₁/0.8185 or 1.222·R = (6.37×10⁶ m)/0.8185 = 7.783×10⁶ m

Hence at an altitude = 1.413×10⁶ m the weight of the object will reduce to 67% its earth-surface value

6 0
3 years ago
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