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2 years ago

12

A standard drink is a unit of measurement. in the united states, a standard drink contains 0.6 fluid ounces of alcohol.which of

these drinks represents a standard drink?

1 answer:

lora16 [44]2 years ago

6 0

The example of an alcohol that represents standard drink is 1.5 oz liquor.

<h3>What is standard drink?</h3>

A standard drink is a measure of alcohol consumption representing a hypothetical beverage which contains a fixed amount of pure alcohol.

A standard drink is also a unit of measurement.

In the United States, a standard drink contains 0.6 fluid ounces of alcohol.

Thus, it is the amount of any beverage that contains about 14 grams/0.6 oz of pure alcohol.

Examples of standard drinks:

12 oz beer/hard seltzer,
5 oz wine,
1.5 oz liquor (like vodka or rum)

Thus, the example of an alcohol that represents standard drink is 1.5 oz liquor.

Learn more about standard drinks here: brainly.com/question/17645986

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You turn on your car's headlights while driving at night. What transformation is taking place?

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What is the kinetic energy of a 9.0 kg steelhead if its speed is 16 m/s?

Vesnalui [34]

<u>We are given:</u>

Mass of the Steelhead(m) = 9 kg

Velocity of the Steelhead(v) = 16 m/s

<u>Calculating the Kinetic Energy:</u>

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3 years ago

If an object is to rest on an incline without slipping, then friction must equal the component of the weight of the object paral

leonid [27]

Answer:

$\theta = tan^{-1}\mu$

Explanation:

As we know that if the object is placed on the inclined plane then the force of friction on the object is counterbalanced by the component of the weight of the object along the inclined plane.

So we can say

$F_f = mgsin\theta$

now if we increase the inclination of the plane then the component of the weight weight along the inclined plane will increase and hence the friction force will also increase.

As we know that the limiting value or the maximum value of friction force at the static condition is given by

$F_f = \mu N$

$N = mg cos\theta$

so we have

$F_f = \mu (mg cos\theta)$

so we will have

$mg sin\theta = \mu (mg cos\theta)$

so now we have

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3 0

3 years ago

What is the heat capacity of an object at 25.5∘C that absorbs 45 kJ of heat and is heated to 28.2∘C?

sergey [27]

Answer:

16.6 kJ/°C

Explanation:

given,

Amount of heat absorbed = 45 kJ

initial temperature, T₁ = 25.5°C

final temperature, T₂ = 28.2°C

change in temperature = T₂ - T₁

= 28.2 - 25.5 = 2.7° C

$Heat\ capacity = \dfrac{Heat\ absorbed}{\Delta T}$

$Heat\ capacity = \dfrac{45\ kJ}{2.7}$

$Heat\ capacity = 16.6\ kJ/^0C$

Heat capacity of the object is equal to 16.6 kJ/°C

4 0

4 years ago

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A solid uniform cylinder of mass 4.1 kg and radius 0.057 m rolls without slipping at a speed of 0.79 m/s. What is the cylinder’s

Amiraneli [1.4K]

Answer:

The cylinder’s total kinetic energy is 1.918 J.

Explanation:

Given that,

Mass = 4.1 kg

Radius = 0.057 m

Speed = 0.79 m/s

We need to calculate the linear kinetic energy

Using formula of linear kinetic energy

$K.E_{l}=\dfrac{1}{2}mv^2$

$K.E_{l}=\dfrac{1}{2}\times4.1\times(0.79)^2$

$K.E_{l}=1.279\ J$

We need to calculate the rotational kinetic energy

$K.E_{r}=\dfrac{1}{2}\times I\omega^2$

$K.E_{r}=\dfrac{1}{2}\times\dfrac{1}{2}\times mr^2\times(\dfrac{v}{r})^2$

$K.E_{r}=\dfrac{1}{4}\times m\times v^2$

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$K.E_{r}=0.639\ J$

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$K.E=K.E_{l}+K.E_{r}$

$K.E=1.279+0.639$

$K.E=1.918\ J$

Hence, The cylinder’s total kinetic energy is 1.918 J.

8 0

4 years ago