The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as

<h3>What is the formula for the area of the shaded region in the figure?</h3>
Parameters



Generally, the equation for the Area is mathematically given as
![& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\](https://tex.z-dn.net/?f=%26%20A%3D2%20%5Cint_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%5Cleft%28h-%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%20p%7D%5Cright%29%20d%20x%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%28h%20x-%5Cfrac%7Bx%5E%7B3%7D%7D%7B12%20p%7D%5Cright%5D_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%5B%5Cleft%5Bh%202%20%5Csqrt%7Bp%20h%7D-%5Cfrac%7B1%7D%7B12%20p%7D%20%5Ccdot%282%20%5Csqrt%7Bp%20h%7D%29%5E%7B3%7D-0%5Cright%5D%5Cright.%20%5C%5C)
![&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h](https://tex.z-dn.net/?f=%26A%3D2%5Cleft%5B2%20h%5E%7B3%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B8%28%5Csqrt%7Bp%7D%29%5E%7B3%7D%28%5Csqrt%7Bh%7D%29%5E%7B3%7D%7D%7B12%20p%7D-0%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%5Cleft%5B2%20h%5E%7Bk%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B2%7D%7B3%7D%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%20%5Ctimes%20%5Cfrac%7B4%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%7D%7B3%7D%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Ccdot%20%5Csqrt%7Bp%7D%20%5Ccdot%20%5Csqrt%7Bh%7D%20%5Ccdot%20h%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Csqrt%7Bp%20h%7D%20%5Ccdot%20h)

In conclusion, the equation for the Area is

Read more about Area
brainly.com/question/27683633
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Answer:
y= -0.3x - 5.6
Step-by-step explanation:
m= (-5)-(-8)/(-2)-8
m= -0.3
y=mx+c
-8= -0.3(8)+c
-8= -2.4 +c
-8+2.4=c
c= -28/5
y= -0.3x - 5.6
the answer is .91 because you have to move the decimal two places to the left
Answer:
12
Step-by-step explanation:
You need to find the least common denominator (LCD) to all the denominators of the fractions present in the equation. These denominators are (writing them in their prime factor form to make our calculations easier):
Therefore, we need to include a factor of 3, and two factors of 2 (
) in our least common denominator, so this LCD will be a perfectly divided by all three given denominators, therefore eliminating all fractions in the equation.
Our LCD is = 