<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
B. y=-10,250
C. 6 payments
Sorry for my terrible handwriting.. Hope this helps tho! Have a great day/night!
Answer:
I think its supliment but I took this class a long time ago so don't quote me on that
Step-by-step explanation:
B is the answer to the question
Answer:
x ≤ 0
Step-by-step explanation:
2x² ≤ 0
2x² / 2 ≤ 0 / 2
x² ≤ 0
x²/ x ≤ 0 / x
x ≤ 0
