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Contact [7]
3 years ago
13

Which of the following is an electromagnetic wave

Physics
2 answers:
andreev551 [17]3 years ago
5 0
Sound has an electromagnetic wave
balandron [24]3 years ago
4 0

Answer:

The answer is D. Sound

Explanation:

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Diffinition of nebula
GrogVix [38]

nebulae, nebulæ, or nebulas) is an interstellar cloud of dust, hydrogen, helium and other ionized gases. Originally, nebula was a name for any diffuse astronomical object, including galaxies beyond the Milky Way. The Andromeda Galaxy, for instance, was once referred to as the Andromeda Nebula (and spiral galaxies in general as "spiral nebulae") before the true nature of galaxies was confirmed in the early 20th century by Vesto Slipher, Edwin Hubble and others.

Most nebulae are of vast size, even hundreds of light years in diameter.[3] Although denser than the space surrounding them, most nebulae are far less dense than any vacuum created on Earth – a nebular cloud the size of the Earth would have a total mass of only a few kilograms. Many nebulae are visible due to their fluorescence caused by the embedded hot stars, while others are so diffuse they can only be detected with long exposures and special filters. Some nebulae, are variably illuminated by T Tauri variable stars. Nebulae are often star-forming regions, such as in the "Pillars of Creation" in the Eagle Nebula. In these regions the formations of gas, dust, and other materials "clump" together to form denser regions, which attract further matter, and eventually will become dense enough to form stars. The remaining material is then believed to form planets and other planetary system objects.

The range of objects called nebula are very diverse, have diverse origins, and final ends.

Contents <span> [hide] </span><span><span>1Observational history</span><span>2Formation</span><span><span>3Types of nebulae</span><span><span>3.1Classical types</span><span>3.2Diffuse nebulae</span><span><span>3.3Planetary nebulae</span><span>3.3.1Protoplanetary nebula</span></span><span>3.4Supernova remnants</span></span></span><span><span>4Notable named nebulae</span><span>4.1Nebula catalogs</span></span><span>5See also</span><span>6References</span><span>7<span>External links

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7 0
4 years ago
A model rocket blasts off and moves upward with an acceleration of 12 m/s2 until it reaches a height of 26 m. at that height, it
Diano4ka-milaya [45]

initial acceleration of rocket is given as

a = 12 m/s^2

h = 26 m

now we can use kinematics to find its speed

v_f^2 - v_i^2 = 2 a h

v_f^2 - 0 = 2 * 12*26

v_f = 24.98 m/s

now after this it will be under free fall

so now again using kinematics

v_f = 0

at maximum height

v_f^2 - v_i^2 = 2 a s

0 - 24.98^2 = 2 * (-9.8)* h

h = 31.8 m

total height from the ground = 31.8 + 26 = 57.8 m

Part b)

now after reaching highest height it will fall to ground

So in order to find the speed we can use kinematics again

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2*9.8*57.8

v_f = 33.67 m/s

Part c)

first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s

now we have

v_f - v_i = a t

24.98 - 0 = 12*t_1

t_1 = 2.1 s

after this it will reach to highest point and final speed becomes zero

v_f - v_i = at

0 - 24.98 = -9.8 * t

t_2 = 2.55 s

now from this it will fall back to ground and reach to final speed 33.67 m/s

now we have

v_f - v_i = at

33.67 - 0 = 9.8 * t

t_3 = 3.44 s

so total time is given as

<em>t = 3.44 + 2.55 + 2.1 = 8.1 s</em>

5 0
3 years ago
Please i need help what happens to water once it reaches the earths surface!!!??????
Zina [86]
It is called condensation 
8 0
3 years ago
Which of the following forces is MOST involved in radioactive decay?
mario62 [17]
Weak nuclear force is the most involved
3 0
3 years ago
Read 2 more answers
Consider an insulated tank with a volume V = 2 L is separated into two equal-volume parts by a thin wall. On the left is an idea
steposvetlana [31]

Answer

given,

V = 2 L

the left is an ideal gas at  P = 100 k Pa and T = 500 K

mass is constant

 m_1 = m_2

\dfrac{P_1V_1}{RT_1} = \dfrac{P_2V_2}{RT_2}

Pressure is same because it's not changing due to process

\dfrac{V}{500} = \dfrac{2 V}{T_2}

T_2 = 1000\ K

\Delta S_{univ} = \Delta S_{sys} + (\Delta S)_{surr}

\Delta S_{univ} =m(C_v ln (\dfrac{T_2}{T_1}))+ R ln (\dfrac{V_2}{V_1})

m = \dfrac{P_1V_1}{RT_1}

m = \dfrac{100 \times 10^3 \times 2 \times 10^{-3}}{287\times 500}

m = 1.39 x 10⁻³ Kg

\Delta S_{univ} =1.39\times 10^{-3}(0.718 ln\ 2+ 0.287 ln (2)

\Delta S_{univ} =0.968\times 10^{-3}\ kJ/K

5 0
3 years ago
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