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Bumek [7]
3 years ago
7

Two iron balls of different mass are heated to 100°C and dropped in water. If the same amount of heat is lost by the two balls t

o water, what can be said about the final temperatures of the two balls? (Heat lost = mCpΔT, where m = mass of the object, Cp = specific heat capacity of the material, and ΔT = change in temperature). A) Both balls will have the same temperature as the heat lost by both balls is the same. B) Both balls will have the same temperature as the specific heat capacities of both balls are the same. C) The lighter ball will have a higher temperature because the change of temperature is directly proportional to mass. D) The heavier ball will have a higher temperature because the change of temperature is inversely proportional to mass.
Physics
2 answers:
lisov135 [29]3 years ago
5 0

Answer:

The correct option is D) The heavier ball will have a higher temperature because the change of temperature is inversely proportional to mass.

Explanation:

The measurement and calculation of the amounts of heat exchanged by a body or system is called calorimetry.

In this way, there is a direct proportionality relationship between heat and temperature (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also; and the same occurs when either of them decreases .). The constant of proportionality depends on the substance that constitutes the body as its mass, and the product of specific heat results from the body's mass. So, the equation that allows you to calculate heat exchanges is:

Q = Cp * m * ΔT

Where Q is the heat exchanged in Joules for a body of mass m in grams, constituted by a specific heat substance Cp measured in joule per gram degree Celsius and where ΔT is the temperature variation measured in degree Celsius. The temperature variation is ΔT=Tfinal - Tinitical

Then the temperature variation will be:

ΔT=\frac{Q}{Cp*m}

In this expression you can see that it follows the model of a rule of inverse proportionality y=\frac{k}{x}. k is a constant that in this case is represented by Q and Cp. So, the change of temperature is inversely proportional to mass.

Finally <u><em>the correct option is D) The heavier ball will have a higher temperature because the change of temperature is inversely proportional to mass. </em></u>

luda_lava [24]3 years ago
3 0
The correct answer for this question is this one:"D) The heavier ball will have a higher temperature because the change of temperature is inversely proportional to mass."<span>
</span>Hope this helps answer your question and have a nice day ahead.
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Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg

where m_a is the mass of the arrow, m_b is the mass of the block, \Delta H of the change in height of the block after the collision, and v is the velocity of the arrow before it hit the block.

Solving for the velocity v, we get:

$v = \sqrt{\frac{2(m_b+m_a)\Delta Hg}{m_a} } $

and we put in the numerical values

m_a = 0.045kg,

m_b = 1.40kg,

\Delta H = 0.4m,

g= 9.8m/s^2

and simplify to get:

\boxed{ v= 15.9m/s}

The arrow was moving at 15.9 m/s

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3 years ago
A 0.00275 kg air‑inflated balloon is given an excess negative charge q1 =−3.50×10−8 C by rubbing it with a blanket. It is found
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Answer:

1)  \rm q_2 is<u> positive.</u>

<u></u>

2) \rm q_2=4.56\times 10^{-10}\ C.

Explanation:

<h2><u>Part 1:</u></h2>

<u></u>

The charged rod is held above the balloon and the weight of the balloon acts in downwards direction. To balance the weight of the balloon, the force on the balloon due to the rod must be directed along the upwards direction, which is only possible when the rod exerts an attractive force on the balloon and the electrostatic force on the balloon due to the rod is attractive when the polarities of the charge on the two are different.

Thus, In order for this to occur, the polarity of charge on the rod must be positive, i.e., \rm q_2 is <u>positive.</u>

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<h2><u>Part 2:</u></h2>

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<u>Given:</u>

  • Mass of the balloon, m = 0.00275 kg.
  • Charge on the balloon, \rm q_1 = -3.50\times 10^{-8}\ C.
  • Distance between the rod and the balloon, d = 0.0640 m.
  • Acceleration due to gravity, \rm g = 9.81\ m/s^2.

In order to balloon to be float in air, the weight of the balloom must be balanced with the electrostatic force on the balloon due to rod.

Weight of the balloon, \rm W = mg = 0.00275\times 9.81=2.70\times 10^{-2}\ N.

The magnitude of the electrostatic force on the balloon due to the rod is given by

\rm F_e = \dfrac{1}{4\pi \epsilon_o}\dfrac{|q_1||q_2|}{d^2}.

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\rm F_e = W\\\dfrac{1}{4\pi \epsilon_o}\dfrac{|q_1||q_2|}{d^2}=W\\8.99\times 10^9\times \dfrac{3.50\times10^{-8}\times |q_2| }{0.0640^2}=2.70\times 10^{-2}\\|q_2| = \dfrac{2.70\times 10^{-2}\times 0.00640^2}{8.99\times 10^9\times 2.70\times 10^{-7}}=4.56\times 10^{-10}\ C.

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