a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )
2 = ( v(2) - 10 ) ÷ ( 6 - 0 )
2 × 6 = v(2) - 10
v(2) = 12 + 10
v(2) = 22 m/s
Answer:
-26 m/s.
Explanation:
Hello,
In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

With which we compute the maximum height:

Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:

Which is clearly negative since it the projectile is moving downwards the starting point.
Regards.
Answer:
swimming, cycling, and jogging
Explanation: