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3 years ago

a 10N force is exerted on a box moving it 20m in the same direction what is the magnitude of work done on the box

Physics

2 answers:

labwork [276]3 years ago

8 0

Answer : Work done, W = 200 J.

Explanation :

Given that,

Force exerted on the box, F = 10 N

Distance covered by the box, d = 20 m

The angle between the force and the displacement is 0 as both are acting in same direction.

Work done on the box is given by :

W = F.d

$W=10\ N\times 20\ m$

W = 200 J

So, the work done on the box is 200 J.

Hence, this is the required solution.

Marta_Voda [28]3 years ago

6 0

The formula for work is
W = F*s
where W = work, F = force, s = displacement
Given that F = 10 N and s = 20 m, therefore
W = (10 N)(20 m) = 200 N*m = 200 J

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Answer:

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3 years ago

The terminal velocity is not dependent on which one of the following properties? the drag coefficient 1 the force of gravity 2 c

ahrayia [7]

<h2>Answer: the falling time</h2>

Explanation:

When a body or object falls, basically two forces act on it:

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$C_ {d}$ is the drag coefficient

$\rho$ is the density of the fluid (air for example)

$V$ is the velocity

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So, this force is proportional to the transversal area of the falling element and to the square of the velocity.

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Where:

$m$ is the mass of the object

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So, at the moment when the drag force equals the gravity force, the object will have its terminal velocity:

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As we can see, there is no "falling time" in this equation.

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3 years ago

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3 0

3 years ago

What is the force of an object with a mass of 30 kg that is free falling?

disa [49]

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